printing - 尚未指定运行报告所需的一个或多个参数

Question

我正在尝试直接打印 RDLC 文件而不显示 Microsoft Report Viewer，我已按照 MSDN's example 进行操作。但现在，每次我调用 LocalReport 类实例的“Render”方法时，它都会抛出“尚未指定运行报表所需的一个或多个参数”。异常。

谁能告诉我我错过了哪个参数？或者我如何找到有关此异常的更多详细信息？

        LocalReport report = new LocalReport();
        report.ReportPath = System.Windows.Forms.Application.StartupPath + "\\" + rdlcFileName;
        report.EnableExternalImages = true;

        ReportParameter[] reportParams = new ReportParameter[]
        {
            new ReportParameter("LogoAddress", settings.LogoFileName),
            new ReportParameter("FooterValue", settings.InvoicesFooter)
        };
        report.SetParameters(reportParams);

        report.DataSources.Add(new ReportDataSource("Invoice", new PrintableInvoice[] { invoice }));
        report.DataSources.Add(new ReportDataSource("InvoiceItem", invoiceItems));

        Warning[] warnings;
        try
        {
            string deviceInfo =
                "<DeviceInfo>" +
                "  <OutputFormat>EMF</OutputFormat>" +
                "  <PageWidth>8.5in</PageWidth>" +
                "  <PageHeight>11in</PageHeight>" +
                "  <MarginTop>0.25in</MarginTop>" +
                "  <MarginLeft>0.25in</MarginLeft>" +
                "  <MarginRight>0.25in</MarginRight>" +
                "  <MarginBottom>0.25in</MarginBottom>" +
                "</DeviceInfo>";

            m_streams = new List<Stream>();
            report.Render("Image", deviceInfo, _CreateStream, out warnings);

            foreach( Stream stream in m_streams )
                stream.Position = 0;
        }
        catch( Exception ex )
        {
            System.Diagnostics.Debug.WriteLine(ex.Message);
        }

并且 _CreateStream 是:

    private Stream _CreateStream(string name, string fileNameExtension, Encoding encoding, string mimeType, bool willSeek)
    {
        Stream stream = new FileStream(name + "." + fileNameExtension, FileMode.Create);
        m_streams.Add(stream);
        return stream;
    }

Answer 1

我刚刚发现您是否将参数值作为空字符串传递，例如parameter =“”它会给你这个错误

花了我一段时间