java - 当用户在Java中输入并打印时，for循环跳过索引0

Question

例如，我输入的人数为 3 名学生。它在打印时也会跳过控制台中的索引 0。

Please refer to this image, I have a sample size of 3 students and its output.

我一点也不知道为什么它会跳过索引 0？感谢您的帮助!

import java.util.Arrays;
import java.util.Scanner;

class string{

    public static void main(String [] args){
        Scanner console = new Scanner(System.in);
        
        System.out.print("Enter Student Size: ");
        int studentSize = console.nextInt();
        String [] arrName = new String[studentSize];

        for (int i=0; i<arrName.length; i++){
            System.out.print("Enter student name: ");
            String nameString = console.nextLine();
            arrName[i] = nameString;
        }

        System.out.print(Arrays.toString(arrName));

        //Closing Braces for Class and Main
    }
}

Answer 1

问题出在 console.nextInt() 上，该函数仅读取 int 值。因此在循环内的代码中 console.nextLine() 第一次跳过获取输入。只需将 console.nextLine() 放在 console.nextInt() 之后你可以解决问题。

public static void main(String [] args){
        Scanner console = new Scanner(System.in);

        System.out.print("Enter Student Size: ");
        int studentSize = console.nextInt();
        console.nextLine();
        String [] arrName = new String[studentSize];

        for (int i=0; i<arrName.length; i++){
            System.out.print("Enter student name: ");
            String nameString = console.nextLine();
            arrName[i] = nameString;
        }

        System.out.print(Arrays.toString(arrName));

        //Closing Braces for Class and Main

    }