gpt4 book ai didi

java - 将物体移动到一起

转载 作者:行者123 更新时间:2023-12-02 08:59:21 25 4
gpt4 key购买 nike

编写一个公共(public)实例方法 move(),它采用两个整数参数,表示实例变量 xPos 和 yPos 值的更改量。该方法不应返回任何值。它应该利用提供的方法delay()来暂停,以便重复运行该方法的效果可见,例如this.delay(20);

暂停执行 20 毫秒。

通过移动 StickFigure 的实例并检查它是否保持对齐来测试您的代码。

我的代码如下,但我似乎无法弄清楚如何将所有 3 个形状移动到一起,只有三角形似乎在移动。

public class StickFigure
{
/*Instance variables*/
private int xPos;//The horizontal position of a StickFigure
private int yPos;//The vertical position of a StickFigure
private Circle head;
private Triangle body;
private Rectangle leg;
// add your declarations here for part (a)(i)

/**
* Constructor for objects of class StickFigure that
* provides a default stick figure near the bottom left corner of the graphical display.
*
*/
public StickFigure()
{
super();
this.head = new Circle (30, OUColour.PINK);
this.body = new Triangle (50, 50, OUColour.RED);
this.leg = new Rectangle (6, 50, OUColour.PINK);
this.setXPos(25); //sets starting position towards bottom left of Shapes window
this.setYPos(220);
this.alignAll();
}

/**
* Sets the xPos of the receiver to the value of the argument.
*/
public void setXPos(int newPos)
{
this.xPos = newPos;
this.body.setXPos(newPos);
this.alignAll();
//part (b)(iii)
}

/**
* Returns the xPos of the receiver.
*/
public int getXPos()
{
return this.xPos;
}

/**
* Sets the yPos of the receiver to the value of the argument.
*/
public void setYPos(int newPos)
{
this.yPos = newPos;
this.body.setYPos(newPos);
this.alignAll();

//part (b)(iii)
}

/**
* Returns the yPos of the receiver.
*/
public int getYPos()
{
return this.yPos;
}

/**You will need to uncomment these methods when directed to*******/

/**
* Returns a reference to the head of the receiver.
*/
public Circle getHead()
{
return this.head;
}

/**
* Returns a reference to the body of the receiver.
*/
public Triangle getBody()
{
return this.body;
}

/**
* Returns a reference to the leg of the receiver.
*/
public Rectangle getLeg()
{
return this.leg;
}

/**
* Aligns the head of the receiver relative to the xPos and yPos of the body.
*/
public void alignHead()
{
this.head.setXPos(this.body.getXPos() + (this.body.getWidth() - this.head.getDiameter())/2);
this.head.setYPos(this.body.getYPos() - this.head.getDiameter());
}

/**
* Aligns the body of the receiver relative to the xPos and yPos of the head.
*/
public void alignBody()
{
this.body.setXPos(25);
this.body.setYPos(220);
}

/**
* Aligns the leg of the receiver relative to the xPos and yPos of the head and body.
*/
public void alignLeg()
{
this.leg.setXPos(this.body.getXPos() + (this.body.getWidth() - this.leg.getWidth())/2);
this.leg.setYPos(this.body.getYPos() + this.leg.getHeight());
}

/**
* Aligns all the body parts of the receiver to form the
* StickFigure-type figure.
*/

public void alignAll()
{
this.alignBody();
this.alignHead();
this.alignLeg();
}

public void move(int xPos, int yPos)
{
this.alignAll();
this.body.setXPos(xPos + xPos);
this.body.setYPos(yPos + yPos);
this.delay(20);


}

最佳答案

你的move()不应该设置xPos和yPos吗?所以:

 this.body.setXPos(xPos + xPos);
this.body.setYPos(yPos + yPos);

应该是

 this.setXPos(this.xPos + xPos);
this.setYPos(this.yPos + yPos);

随后alignAll()

然后你的alignBody()说:“将接收器的 body 相对于头部的xPos和yPos对齐”,但你的方法没有这样做......看起来头/腿是相对于 body 而言的。那么也许主体 X、Y 应该相对于 xPos 和 yPos?

关于java - 将物体移动到一起,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60280678/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com