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sql-server - T-sql 在字段更改时重置行号

转载 作者:行者123 更新时间:2023-12-02 08:59:17 25 4
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类似于我最近的一篇文章“t-sql顺序持续时间”,但不完全相同,我想根据x列(在我的例子中为“who”列)的变化来重置行号。

这是返回原始数据的小样本的第一个查询:

SELECT      DISTINCT chr.custno, 
CAST(LEFT(CONVERT( VARCHAR(20),chr.moddate,112),10)+ ' ' + chr.modtime AS DATETIME)as moddate,
chr.who
FROM <TABLE> chr
WHERE chr.custno = 581827
AND LEFT(chr.who, 5) = 'EMSZC'
AND chr.[description] NOT LIKE 'Recalled and viewed this customer'
ORDER BY chr.custno

结果:

custno      moddate             who
581827 2012-11-08 08:38:00.000 EMSZC14
581827 2012-11-08 08:41:10.000 EMSZC14
581827 2012-11-08 08:53:46.000 EMSZC14
581827 2012-11-08 08:57:04.000 EMSZC14
581827 2012-11-08 08:58:35.000 EMSZC14
581827 2012-11-08 08:59:13.000 EMSZC14
581827 2012-11-08 09:00:06.000 EMSZC14
581827 2012-11-08 09:04:39.000 EMSZC49 Reset row number to 1
581827 2012-11-08 09:05:04.000 EMSZC49
581827 2012-11-08 09:06:32.000 EMSZC49
581827 2012-11-08 09:12:03.000 EMSZC49
581827 2012-11-08 09:12:38.000 EMSZC49
581827 2012-11-08 09:14:18.000 EMSZC49
581827 2012-11-08 09:17:35.000 EMSZC14 Reset row number to 1

第二步是添加行号(我在第一个查询中没有这样做,因为使用了单词 DISTINCT);所以……

WITH c1 AS (
SELECT DISTINCT chr.custno
CAST(LEFT(CONVERT( VARCHAR(20),chr.moddate,112),10)+ ' ' + chr.modtime AS DATETIME)as moddate,
chr.who
FROM <TABLE> chr
WHERE chr.custno = 581827
AND LEFT(chr.who, 5) = 'EMSZC'
AND chr.[description] NOT LIKE 'Recalled and viewed this customer'
)

SELECT ROW_NUMBER() OVER (PARTITION BY custno ORDER BY custno, moddate, who) AS RowID, custno, moddate, who
FROM c1

结果:

RowID   custno      moddate                      who
1 581827 2012-11-08 08:38:00.000 EMSZC14
2 581827 2012-11-08 08:41:10.000 EMSZC14
3 581827 2012-11-08 08:53:46.000 EMSZC14
4 581827 2012-11-08 08:57:04.000 EMSZC14
5 581827 2012-11-08 08:58:35.000 EMSZC14
6 581827 2012-11-08 08:59:13.000 EMSZC14
7 581827 2012-11-08 09:00:06.000 EMSZC14
8 581827 2012-11-08 09:04:39.000 EMSZC49 Reset row number to 1
9 581827 2012-11-08 09:05:04.000 EMSZC49
10 581827 2012-11-08 09:06:32.000 EMSZC49
11 581827 2012-11-08 09:12:03.000 EMSZC49
12 581827 2012-11-08 09:12:38.000 EMSZC49
13 581827 2012-11-08 09:14:18.000 EMSZC49
14 581827 2012-11-08 09:17:35.000 EMSZC14 Reset row number to 1

下一步是我陷入困境的地方:目标是在“who”列中的值每次更改时将 RowID 重置为 1。下面的代码得到了“几乎在那里”的结果(应该注意的是,我从某个地方偷/借了这个代码,但现在我找不到该网站):

WITH c1 AS (
SELECT DISTINCT chr.custno,
CAST(LEFT(CONVERT( VARCHAR(20),chr.moddate,112),10)+ ' ' + chr.modtime AS DATETIME)as moddate,
chr.who
FROM <TABLE> chr
WHERE chr.custno = 581827
AND LEFT(chr.who, 5) = 'EMSZC'
AND chr.[description] NOT LIKE 'Recalled and viewed this customer'
)
, c1a AS (
SELECT ROW_NUMBER() OVER (PARTITION BY custno ORDER BY custno, moddate, who) AS RowID, custno, moddate, who
FROM c1
)

SELECT x.RowID - y.MinID + 1 AS Row,
x.custno, x.Touch, x.moddate, x.who
FROM (
SELECT custno, who, MIN(RowID) AS MinID
FROM c1a
GROUP BY custno, who
) AS y
INNER JOIN c1a x ON x.custno = y.custno AND x.who = y.who

结果:

Row custno      moddate                    who
1 581827 2012-11-08 08:38:00.000 EMSZC14
2 581827 2012-11-08 08:41:10.000 EMSZC14
3 581827 2012-11-08 08:53:46.000 EMSZC14
4 581827 2012-11-08 08:57:04.000 EMSZC14
5 581827 2012-11-08 08:58:35.000 EMSZC14
6 581827 2012-11-08 08:59:13.000 EMSZC14
7 581827 2012-11-08 09:00:06.000 EMSZC14
1 581827 2012-11-08 09:04:39.000 EMSZC49 Reset row number to 1 (Hooray! It worked!)
2 581827 2012-11-08 09:05:04.000 EMSZC49
3 581827 2012-11-08 09:06:32.000 EMSZC49
4 581827 2012-11-08 09:12:03.000 EMSZC49
5 581827 2012-11-08 09:12:38.000 EMSZC49
6 581827 2012-11-08 09:14:18.000 EMSZC49
14 581827 2012-11-08 09:17:35.000 EMSZC14 Reset row number to 1 (Crappies.)

期望的结果:

Row custno      moddate                     who
1 581827 2012-11-08 08:38:00.000 EMSZC14
2 581827 2012-11-08 08:41:10.000 EMSZC14
3 581827 2012-11-08 08:53:46.000 EMSZC14
4 581827 2012-11-08 08:57:04.000 EMSZC14
5 581827 2012-11-08 08:58:35.000 EMSZC14
6 581827 2012-11-08 08:59:13.000 EMSZC14
7 581827 2012-11-08 09:00:06.000 EMSZC14
1 581827 2012-11-08 09:04:39.000 EMSZC49 Reset row number to 1
2 581827 2012-11-08 09:05:04.000 EMSZC49
3 581827 2012-11-08 09:06:32.000 EMSZC49
4 581827 2012-11-08 09:12:03.000 EMSZC49
5 581827 2012-11-08 09:12:38.000 EMSZC49
6 581827 2012-11-08 09:14:18.000 EMSZC49
1 581827 2012-11-08 09:17:35.000 EMSZC14 Reset row number to 1

感谢您的帮助。

最佳答案

如果您使用的是 SQL Server 2012,则可以使用 LAG将值与上一行进行比较,您可以使用 SUMOVER记录更改。

with C1 as
(
select custno,
moddate,
who,
lag(who) over(order by moddate) as lag_who
from chr
),
C2 as
(
select custno,
moddate,
who,
sum(case when who = lag_who then 0 else 1 end)
over(order by moddate rows unbounded preceding) as change
from C1
)
select row_number() over(partition by change order by moddate) as RowID,
custno,
moddate,
who
from C2

SQL Fiddle

更新:

SQL Server 2005 的版本。它使用递归 CTE 和临时表来中间存储需要迭代的数据。

create table #tmp
(
id int primary key,
custno int not null,
moddate datetime not null,
who varchar(10) not null
);

insert into #tmp(id, custno, moddate, who)
select row_number() over(order by moddate),
custno,
moddate,
who
from chr;

with C as
(
select 1 as rowid,
T.id,
T.custno,
T.moddate,
T.who,
cast(null as varchar(10)) as lag_who
from #tmp as T
where T.id = 1
union all
select case when T.who = C.who then C.rowid + 1 else 1 end,
T.id,
T.custno,
T.moddate,
T.who,
C.who
from #tmp as T
inner join C
on T.id = C.id + 1
)
select rowid,
custno,
moddate,
who
from C
option (maxrecursion 0);

drop table #tmp;

SQL Fiddle

关于sql-server - T-sql 在字段更改时重置行号,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13405264/

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