Ansible:将两个列表转换为键、值字典

Question

我有 2 个列表作为 set_fact 并且想要创建一个字典

我运行的是ansible 2.8我有如下列表

  "inventory_devices": [
        "device0", 
        "device1" 
    ]

和列表2如下

"inventory_ips": [
    "10.1.1.1", 
    "10.1.1.2" 
]

我想要得到像这样的输出显示

"inventory_dict": [
    "device0": "10.1.1.1",
    "device1": "10.1.1.2"
]

谢谢。

Answer 1

您可以使用 zip filter built into ansible 完全使用 jinja2 来完成此操作.

To get a list combining the elements of other lists use zip

- name: give me list combo of two lists
  debug:
    msg: "{{ [1,2,3,4,5] | zip(['a','b','c','d','e','f']) | list }}"

...

Similarly to the output of the items2dict filter mentioned above, these filters can be used to contruct a dict:

{{ dict(keys_list | zip(values_list)) }}

zip 过滤器按顺序组合列表对中的项目，而 dict 构造则根据列表对创建字典。

inventory_dict: "{{ dict(inventory_devices | zip(inventory_ips)) }}"