Java控制台无限次打印 "infinity"而不是值？

Question

我正在尝试制作一个程序，用莱布尼兹方程作为 pi 日的属性来估计 pi，但是控制台没有打印出我想要的估计 pi ​​值，而是无限次打印“无穷大”，直到我终止执行。我非常非常困惑，需要帮助!代码:

import java.util.Scanner;
class Main {
  public static void main(String[] args) {
    //in order to celebrate pi day I have made this program that calculates pi with the Leibniz Formula
     System.out.println("enter the number of iterations you want:");
    double EstimatedPi=0;
    Scanner input= new Scanner(System.in);
    double iterations=input.nextDouble();
    double denominator = 1;
    for(int i=0;0<iterations;i++){
      if(i%2 == 0){
        EstimatedPi=EstimatedPi + (1/denominator);
      }
      else{
        EstimatedPi=EstimatedPi-(1/denominator);
      }
      denominator=denominator+2;
      EstimatedPi=EstimatedPi*4;
      System.out.println(EstimatedPi);
    }
  }
}

我认为我在整个程序中没有将任何内容除以零!莱布尼兹公式: https://en.wikipedia.org/wiki/Leibniz_formula_for_π控制台截图: screenshot链接到我的 repl 项目: https://repl.it/@HarryPengRHS/Determining-the-value-of-pi-pi-day-attribute

Answer 1

你的for循环条件是错误的，应该是for (int i = 0; i < iterations; i++)您正在使用 for(int i=0;0<iterations;i++){ 0<iterations这始终是正确的，并且循环会无限。

public class Main {

    public static void main(String[] args) {// in order to celebrate pi day I have made this program that calculates pi
                                            // with the Leibniz Formula
        System.out.println("enter the number of iterations you want:");
        double EstimatedPi = 0;
        Scanner input = new Scanner(System.in);
        double iterations = input.nextDouble();
        double denominator = 1;
        for (int i = 0; i < iterations; i++) {
            if (i % 2 == 0) {
                EstimatedPi = EstimatedPi + (1 / denominator);
            } else {
                EstimatedPi = EstimatedPi - (1 / denominator);
            }
            denominator = denominator + 2;
            EstimatedPi = EstimatedPi * 4;
            System.out.println(EstimatedPi);
        }
    }
}