java - 如何使 args 函数等于 2？因为它只是抛出文件未找到异常

Question

/**
  *   Compilation  : javac Traversal.java
  *   Execution    : java Traversal args0 ----- GraphicsMode
  *                : java Traversal args0 args1 ----- TextMode
  *
  *   Arguments    : args0 - boardfilename.txt
  *                     args1 - movesfilename.txt
  *
  *   Controls     : h - left movement
  *                  l - right movement
  *                  j - down movement
  *                  k - up movement
  **/   
public static void main(String[] args) throws FileNotFoundException, InterruptedException {
        if (args.length == 1) {
            GameBoard board = Middleware.parseArgs(args[0]);
            Middleware.validateBoard(board);
            GraphicsMode.play(board);
        }else if (args.length == 2) {
            GameBoard board = Middleware.parseArgs(args[0]);
            Middleware.validateBoard(board);
            String moves = Middleware.readMoves(new Scanner(new File(args[1])));
            TextMode.play(board, moves);
        }
        exit();
    }

    /**
    * Sleep for 4000 microseconds to allow
    * the final event sound to finish
    * playing and then exits.
    */
    public static void exit() throws InterruptedException {
        Thread.sleep(4000);
        System.exit(0);
    }

Answer 1

正如 JavaDoc 中已经提到的，如果您希望将两个参数传递给程序，则需要从命令提示符(cmd 窗口)运行该程序，如下所示:

java Traversal args0 args1

哪里

args0 - boardfilename.txt                  
args1 - movesfilename.txt

换句话说，将其运行为 java Traversal boardfilename.txt movesfilename.txt从命令提示符。如果boardfilename.txt和movesfilename.txt不在 Traversal.class 的同一位置是，提及他们的完整路径，即

java Traversal path-to-boardfilename.txt path-to-movesfilename.txt

如果您在 Eclipse 中运行它，请右键单击 Traversal.java> 单击运行配置...> 将值放入对话框中，如下所示屏幕截图 > 单击运行

在这种情况下(即当您尝试从 Eclipse 运行它时)，请确保 boardfilename.txt和movesfilename.txt是否在 src 的父文件夹中.