java - 无法获取填写 PDFBox 的路径

Question

我正在使用 PDF 框尝试创建一些具有弯曲边缘的矩形。最终弄清楚如何使用贝塞尔曲线后，我能够得到我喜欢的形状。我现在的问题是我不知道如何填写它。我尝试过在随机点闭合路径，仅使用贝塞尔曲线绘制形状，在随机点抚摸路径，在随机点闭合路径，但它仍然不会填充整个物体。它似乎只填充了曲线的圆形边缘。谁能让我知道我做错了什么？非常感谢。生成器是一个对象，我用它来获取页面中当前设置的水平和垂直位置。在此示例中，水平和垂直位置值没有改变(水平位置为 200，垂直位置为 240)。这是我正在使用的代码(抱歉其中的魔数(Magic Number))

这是 PDF 页面中生成的图像，由于某种原因不会填充:

//Creating PDF document object 
PDDocument document = new PDDocument(); 
//Creating the PDDocumentInformation object 
PDDocumentInformation pdd = document.getDocumentInformation();
generator.drawRectangleWithCurvedBorders(200, 400, cs, generator);



public void drawRectangleWithCurvedBorders(int width, int height, PDPageContentStream contentStream, XClass generator) throws IOException
    {
        contentStream.setStrokingColor( Color.BLACK );
        contentStream.setNonStrokingColor( Color.BLACK );

        // bottom of rectangle
        contentStream.moveTo(generator.getHorizontalPosition() - 0.5f, generator.getVerticalPosition() );
        contentStream.lineTo(generator.getHorizontalPosition() + width + 0.5f, generator.getVerticalPosition() );
        contentStream.moveTo(generator.getHorizontalPosition() + width, generator.getVerticalPosition() );

        contentStream.curveTo(generator.getHorizontalPosition() + width + 5.9f, generator.getVerticalPosition() + 0.14f,
                              generator.getHorizontalPosition() + width + 11.06f, generator.getVerticalPosition() + 5.16f,
                              generator.getHorizontalPosition() + width + 10.96f, generator.getVerticalPosition() + 10);

        // left of rectangle
        contentStream.moveTo(generator.getHorizontalPosition(), generator.getVerticalPosition() );
        contentStream.curveTo(generator.getHorizontalPosition() - 5.9f, generator.getVerticalPosition() + 0.14f,
                              generator.getHorizontalPosition() - 11.06f, generator.getVerticalPosition() + 5.16f,
                              generator.getHorizontalPosition() - 10.96f, generator.getVerticalPosition() + 10);
        contentStream.moveTo(generator.getHorizontalPosition() - 10.96f, generator.getVerticalPosition() + 10 - 0.5f);
        contentStream.lineTo(generator.getHorizontalPosition() - 10.96f, generator.getVerticalPosition() + height + 0.5f );


        // right of rectangle       
        contentStream.moveTo(generator.getHorizontalPosition() + width + 10.96f, generator.getVerticalPosition() + 10 - 0.5f);
        contentStream.lineTo(generator.getHorizontalPosition() + width + 10.96f, generator.getVerticalPosition() + height + 0.5f);
        contentStream.moveTo(generator.getHorizontalPosition() + width, generator.getVerticalPosition() + height + 10);
        contentStream.curveTo(generator.getHorizontalPosition() + width + 5.9f, generator.getVerticalPosition() + height + 0.14f + 10,
                  generator.getHorizontalPosition() + width + 11.06f, generator.getVerticalPosition() + height - 5.16f + 10,
                  generator.getHorizontalPosition() + width + 10.96f, generator.getVerticalPosition() + height);

        // top of rectangle
        contentStream.moveTo(generator.getHorizontalPosition() + width + 0.5f, generator.getVerticalPosition() + height + 10);
        contentStream.lineTo(generator.getHorizontalPosition() - 0.5f, generator.getVerticalPosition() + height + 10);
        contentStream.moveTo(generator.getHorizontalPosition(), generator.getVerticalPosition() + height + 10);
        contentStream.curveTo(generator.getHorizontalPosition() - 5.9f, generator.getVerticalPosition() + height + 0.14f + 10,
                  generator.getHorizontalPosition() - 11.06f, generator.getVerticalPosition() + height - 5.16f + 10,
                  generator.getHorizontalPosition() - 10.96f, generator.getVerticalPosition() + height);

        contentStream.closePath();
        contentStream.fill();
    }

Answer 1

正如 Tilman 在对该问题的评论中已经说过的那样，问题在于许多 moveTo() 指令。事实上，每个 moveTo 都会启动一个新的子路径，并且每个子路径意味着一个单独的填充区域。根据填充变体和子路径方向，这些子路径的交叉点实际上可能被填充排除。

因此，要创建一个具有 OP 概述的弯曲边框的填充矩形，应该重新排列路径构建指令，以便它们勾勒出矩形的轮廓，而不会被 moveTo 打断流量，例如像这样:

try (   PDDocument document = new PDDocument()  ) {
    PDPage page = new PDPage();
    document.addPage(page);
    try (   PDPageContentStream contentStream = new PDPageContentStream(document, page)    ) {
        float x = 100;
        float y = 100;
        float width = 200;
        float height = 300;

        contentStream.setStrokingColor( Color.BLACK );
        contentStream.setNonStrokingColor( Color.BLACK );

        contentStream.moveTo(x, y);

        // bottom of rectangle, left to right
        contentStream.lineTo(x + width, y );
        contentStream.curveTo(x + width + 5.9f, y + 0.14f,
                x + width + 11.06f, y + 5.16f,
                x + width + 10.96f, y + 10);

        // right of rectangle, bottom to top
        contentStream.lineTo(x + width + 10.96f, y + height);
        contentStream.curveTo(x + width + 11.06f, y + height - 5.16f + 10,
                x + width + 5.9f, y + height + 0.14f + 10,
                x + width, y + height + 10);

        // top of rectangle, right to left
        contentStream.lineTo(x, y + height + 10);
        contentStream.curveTo(x - 5.9f, y + height + 0.14f + 10,
                x - 11.06f, y + height - 5.16f + 10,
                x - 10.96f, y + height);

        // left of rectangle, top to bottom
        contentStream.lineTo(x - 10.96f, y + 10);
        contentStream.curveTo(x - 11.06f, y + 5.16f,
                x - 5.9f, y + 0.14f,
                x, y);

        contentStream.closePath();
        contentStream.fill();
    }
    document.save(new File("CurvedBorderRectangleLikeMaht33n-improved.pdf"));
}

( CurvedBorderRectangle 测试 testLikeMaht33nImproved)

(我没有那个XClass生成器对象，所以我使用了两个float变量x和y 相反。)

结果如所期望: