java - 查找数组的修剪平均值(不包括最小值和最大值)

Question

正在寻找数组的修剪平均值，但对如何使用方法实现它感到困惑。请提出有关如何实现并使用某种方法获得实际修剪平均值的任何想法。这就是我目前所拥有的一切。 TIA!

public static void main(String[] args) {
    // Program 1: Average, Min, Max, Trimmed Average of Array
    Scanner in = new Scanner(System.in);
    int array[] = new int[] {88,48,96,85,97,68,97};

    // Calling getMax() method for getting max value
    int max = getMax(array);
    System.out.println("Maximum: " + max);

    // Calling getMin() method for getting min value
    int min = getMin(array);
    System.out.println("Minimum: " + min);

    // calling getAvg() method for getting avg value
    double avg = getAvg(array);
    System.out.println("Average: " + avg);

    // calling getMean() method for getting trimmed mean value
    double mean = getTrim(array);
    System.out.println("Trimmed mean: " + mean);
}

// Method for getting the maximum value
public static int getMax(int[] inputArray) {
    int maxValue = inputArray[0];
    for (int i = 1; i < inputArray.length; i++) {
        if (inputArray[i] > maxValue) {
            maxValue = inputArray[i];
        }
    }
    return maxValue;
}

// Method for getting the minimum value
public static int getMin(int[] inputArray) {
    int minValue = inputArray[0];
    for (int i = 1; i < inputArray.length; i++) {
        if (inputArray[i] < minValue) {
            minValue = inputArray[i];
        }
    }
    return minValue;
}

//Method for getting the avg value
public static double getAvg(int[] inputArray) {
    double total = 0;
    double avg;
    for(int i=0; i<inputArray.length; i++){
        total = total + inputArray[i];
    }
    return avg = total / inputArray.length;
}

//Method for getting the trimmed mean value
public static double getTrim(int[] inputArray) {

}

}

Answer 1

试试这个:

public static double avgExcludingMinMax(int[] inputArray) {
    int max = inputArray[0];
    int min = inputArray[0];
    long sum = 0;
    for(int i = 0; i < inputArray.length; i++){
        sum = sum + inputArray[i];
        if (inputArray[i] > max) {
            max = inputArray[i];
        }
        if (inputArray[i] < min) {
            min = inputArray[i];
        }
    }
    return ((double) (sum - max - min)) / (inputArray.length - 2);
}

请注意，如果 inputArray.length == 0，这将引发异常；

如果您想了解有关此类操作的统计背景的更多信息，请查看 https://en.wikipedia.org/wiki/Trimmed_estimator和 https://en.wikipedia.org/wiki/Winsorizing !