java - 如何在 Java 中使用同一循环来确定三个不同条件的范围？

Question

我想使用同一循环对 countX 和 countX 进行计数，而不是创建三个不同的循环。有什么简单的方法可以解决这个问题吗？

public class Absence {
    private static File file = new File("/Users/naplo.txt");
    private static File file_out = new File("/Users/naplo_out.txt");
    private static BufferedReader br = null;
    private static BufferedWriter bw = null;

    public static void main(String[] args) throws IOException {
        int countSign = 0;
        int countX = 0;
        int countI = 0;
        String sign = "#";
        String absenceX = "X";
        String absenceI = "I";

        try {
            br = new BufferedReader(new FileReader(file));
            bw = new BufferedWriter(new FileWriter(file_out));

            String st;
            while ((st = br.readLine()) != null) {
                for (String element : st.split(" ")) {

                    if (element.matches(sign)) {
                        countSign++;
                        continue;
                    }
                    if (element.matches(absenceX)) {
                        countX++;
                        continue;
                    }
                    if (element.matches(absenceI)) {
                        countI++;
                    }
                }
            }
            System.out.println("2. exerc.: There are " + countSign + " rows int the file with that sign.");
            System.out.println("3. exerc.: There are " + countX + " with sick note, and " + countI + " without sick note!");
        } catch (FileNotFoundException ex) {
            Logger.getLogger(Absence.class.getName()).log(Level.SEVERE, null, ex);
        }
    }
}

文本文件示例:

# 03 26
Jujuba Ibolya IXXXXXX
Maracuja Kolos XXXXXXX

Answer 1

我认为您的意思是使用少于 3 个 if 语句。实际上你可以这样，没有 ifs。

在 for 循环中写下:

Countsign += (element.matches(sign)) ? 1 : 0;
CountX += (element.matches(absenceX)) ? 1 : 0;
CountI += (element.matches(absenceI)) ? 1 : 0;