java - 按照与另一个数组 java 相同的顺序对列表对象进行排序

Question

您好，我想订购部门对象的员工列表，但我在数组中存储了顺序，这里是对象和示例

public class Employee {

    private String name;
    private int age;
    private double salary;
    private Department department;
    public Employee(String name, int age, double salary, Department department) {
        ...
    }

    // standard getters, setters and toString
 }

public class Department  {

    private Integer id;
    private String name;

    public Department(Integer id, String name) {
        ...
    }

    // standard getters, setters and toString
}

       Department[] departments = new Department[] {
                new Department(1, "Computing" ), new Department(2, "Human Resources"),
                new Department(3, "administration"), new Department(4, "operations"),
                new Department(5, "marketing"), new Department(6, "communication")
        };

  Employee[] employees = new Employee[] {
                new Employee("John", 23, 5000, departments[5]), new Employee("Steve", 26, 6000, departments[3]),
                new Employee("Frank", 33, 7000,departments[4]), new Employee("Earl", 43, 10000, departments[2]),
                new Employee("Jessica", 23, 4000, departments[1]), new Employee("Pearl", 33, 6000, departments[0])};


        String[] arrOrderDepartment = new String[]{"marketing", "Computing", "administration", "Human Resources", "communication", "operations"};

底线是按部门排列顺序排列的员工

employeesSortedByDepartment = [Employee{"Frank", 33, 7000, Department{id=5, name='marketing'}},Employee{ "Jessica", 23, 4000, Department{id=6, name='communication'} },Employee{"Steve", 26, 6000, Department{id=3, name='administration'} },Employee{"Earl", 43, 10000, Department{id=2, name='Human Resources'}},Employee{ "Pearl", 33, 6000, =Department{id=6, name='communication'} },Employee{ "John", 23, 5000, Department{id=4, name='operations'} }];

我在工作时使用了一些东西，但它没有给我预期的结果

 Collections.sort(department, new Comparator<String>(){
            public int compare(String left, String right) {
                return arrOrderDepartment[stringList.indexOf(left)] - arrOrder[stringList.indexOf(right)];
            }
        });

我使用的是java 6

非常感谢您能帮助我

Answer 1

您可以按如下方式进行:

public class Main {
    public static void main(String[] args) {
        Department[] departments = new Department[] { new Department(1, "Computing"),
                new Department(2, "Human Resources"), new Department(3, "administration"),
                new Department(4, "operations"), new Department(5, "marketing"), new Department(6, "communication") };

        Employee[] employees = new Employee[] { new Employee("John", 23, 5000, departments[5]),
                new Employee("Steve", 26, 6000, departments[3]), new Employee("Frank", 33, 7000, departments[4]),
                new Employee("Earl", 43, 10000, departments[2]), new Employee("Jessica", 23, 4000, departments[1]),
                new Employee("Pearl", 33, 6000, departments[0]) };

        String[] arrOrderDepartment = new String[] { "marketing", "Computing", "administration", "Human Resources",
                "communication", "operations" };
        Employee[] employeesSortedByDepartment = new Employee[employees.length];
        for (int i = 0; i < arrOrderDepartment.length; i++) {
            employeesSortedByDepartment[i] = getEmployeeByDeptId(employees,
                    findDeptIdByDeptName(departments, arrOrderDepartment[i]));
        }
        for (Employee employee : employeesSortedByDepartment) {
            System.out.println(employee);
        }
    }

    static int findDeptIdByDeptName(Department[] departments, String departmentName) {
        for (int i = 0; i < departments.length; i++) {
            if (departments[i].getName().equalsIgnoreCase(departmentName)) {
                return departments[i].getId();
            }
        }
        return -1;
    }

    static Employee getEmployeeByDeptId(Employee[] employees, int id) {
        for (Employee employee : employees) {
            if (employee.getDepartment().getId() == id) {
                return employee;
            }
        }
        return null;
    }
}

输出:

Employee [name=Frank, age=33, salary=7000.0, department=Department [id=5, name=marketing]]
Employee [name=Pearl, age=33, salary=6000.0, department=Department [id=1, name=Computing]]
Employee [name=Earl, age=43, salary=10000.0, department=Department [id=3, name=administration]]
Employee [name=Jessica, age=23, salary=4000.0, department=Department [id=2, name=Human Resources]]
Employee [name=John, age=23, salary=5000.0, department=Department [id=6, name=communication]]
Employee [name=Steve, age=26, salary=6000.0, department=Department [id=4, name=operations]]