object - 命令行参数 - 需要对象 : 'objshell.NameSpace(...)'

Question

我正在编写一个脚本，该脚本将利用 Windows 的内置功能来解压缩提供的 .zip 文件。我对 vbscript 还很陌生，所以有些语法让我有点困惑。我正在使用一些现有代码并尝试修改它，以便它将采用命令行选项作为文件名。如果我使用命令行传递文件名，我会收到错误:

object required: 'objshell.NameSpace(...)'

如果我在脚本中使用文本填充同一变量，则脚本运行时不会出错。尝试使用命令参数时是否还缺少其他一些内容？

这是我的代码:

Option Explicit

Dim sDestinationDirectory,sLogDestination,fso,outLog,sJunk,sSourceFile

sDestinationDirectory = "C:\scripts\vbscriptTemplates\unzip"
sLogDestination = "C:\scripts\vbscriptTemplates\"

Set fso=CreateObject("Scripting.FileSystemObject")
Set outLog = fso.OpenTextFile("unzipRIP.log", 2, True)
If WScript.Arguments.Count = 1 Then
    sSourceFile = WScript.Arguments.Item(0)     'Using this line the code will fail.
    'sSourceFile = "C:\scripts\vbscriptTemplates\test.zip"     'Using this line the code will run.
    outLog.WriteLine ".:|Processing new zip file|:."
    outLog.WriteLine "Processing file: " & sSourceFile
    Extract sSourceFile,sDestinationDirectory
Else
    sJunk = MsgBox("File to be processed could not be found. Please verify.",0,"Unzip - File not found")
    outLog.WriteLine "File to be processed could not be found. Please verify."
    outLog.Close
    Wscript.Quit
End If

Sub Extract( ByVal myZipFile, ByVal myTargetDir )
    Dim intOptions, objShell, objSource, objTarget

    outLog.WriteLine "Processing file in subroutine: " & myZipFile & " target " & myTargetDir
    ' Create the required Shell objects
    Set objShell = CreateObject( "Shell.Application" )

    ' Create a reference to the files and folders in the ZIP file
    Set objSource = objShell.NameSpace( myZipFile ).Items()

    ' Create a reference to the target folder
    Set objTarget = objShell.NameSpace( myTargetDir )
    intOptions = 4

    ' UnZIP the files
    objTarget.CopyHere objSource, intOptions

    ' Release the objects
    Set objSource = Nothing
    Set objTarget = Nothing
    Set objShell  = Nothing
End Sub

引用的行是

sSourceFile = WScript.Arguments.Item(0)

这是我对 Rob van der Woude 编写的代码进行修改的尝试。 http://www.robvanderwoude.com/vbstech_files_zip.php#CopyHereUNZIP

Answer 1

尝试

Set fso = CreateObject("Scripting.FileSystemObject")
sSourceFile = fso.GetAbsolutePathName(WScript.Arguments.Item(0))

而不是

sSourceFile = WScript.Arguments.Item(0)