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c - 不可能的事情发生了!这是什么意思?

转载 作者:行者123 更新时间:2023-12-02 08:38:20 27 4
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我遇到了一个有趣的运行时错误。我认为这是某种内存泄漏。我编写了以下程序:

C代码:

#include <gmp.h>
#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <string.h>
#define PRECISION 4096
#define DECIMAL_POINT 1
#define NULL_TERMINATOR 1

void gatherSquares(const uint32_t limit, uint32_t ** const arr, uint32_t * const count);
uint32_t inList(const uint32_t n, const uint32_t * const arr, const uint32_t count);
void print_help(const char * const str);

int main(int argc, char* argv[]) {
uint32_t limit = 100; /* default */
uint32_t digits = 100; /* default */
uint32_t i,j,sum,bufLen,charCount,sqCount=10;
uint32_t *squares;
char *buffer;
mpf_t irrational;

if(argc > 1 && !strcmp(argv[1],"--help"))
return print_help(argv[0]), EXIT_SUCCESS;
if(argc > 1) sscanf(argv[1],"%u",&limit );
if(argc > 2) sscanf(argv[2],"%u",&digits);

mpf_set_default_prec(PRECISION);
mpf_init(irrational);

charCount = digits + DECIMAL_POINT;
bufLen = charCount + NULL_TERMINATOR;

gatherSquares(limit,&squares,&sqCount);
buffer = malloc(bufLen * sizeof *buffer);

for(i=sum=0; i<=limit; ++i) {
if(inList(i,squares,sqCount))
continue;
mpf_sqrt_ui(irrational,i);
gmp_snprintf(buffer,bufLen,"%.*Ff",charCount,irrational);
for(j=0; j<digits+DECIMAL_POINT; ++j)
if(buffer[j]!='.')
sum += buffer[j]-'0';
}
printf("%u\n",sum);
return EXIT_SUCCESS;
}

void gatherSquares(const uint32_t limit, uint32_t ** const arr, uint32_t * const count) {
uint32_t i,sq,size;
size=10;
*arr = malloc(size * sizeof **arr);
for(i=0; (sq=i*i)<=limit; ++i) {
if(*count > size)
*arr = realloc(*arr, (size*=2) * sizeof **arr);
(*arr)[i] = sq;
}
*arr = realloc(*arr, i * sizeof **arr);
*count = i;
}

uint32_t inList(const uint32_t n, const uint32_t * const arr, const uint32_t count) {
uint32_t hi,mid,low;
hi = count; /* exclusive upper bound */
low = 0; /* inclusive lower bound */
while(low < hi) {
mid = low/2 + hi/2;
if(arr[mid]==n)
return 1;
if(arr[mid] >n)
hi = mid;
else
low = mid + 1;
}
return 0;
}

void print_help(const char * const str) {
printf(" Usage: %s <limit> <digits>\n",str);
printf(" Calculates the digital sum of the first <digits> digits \n");
printf(" of each irrational square root <= <limit>\n");
printf(" * limit : a decimal number\n");
printf(" : default = 100\n");
printf(" * digits : a decimal number\n");
printf(" : default = 100\n");
}

我使用默认设置运行程序 ./a.out一切正常。然后我决定尝试使用更高的搜索空间运行该程序 ./a.out 1000 .这产生了以下输出:
user@comp:~/Current/Working/Directory ./a.out 1000 
a.out: malloc.c:2369: sysmalloc: Assertion `(old_top == (((mbinptr) (((char *)
&((av)->bins[((1) - 1) * 2])) - __builtin_offsetof (struct malloc_chunk,fd)))) &&
old_size == 0) || ((unsigned long) (old_size) >=
(unsigned long)((((__builtin_offsetof (struct malloc_chunk, fd_nextsize))+
((2 * (sizeof(size_t))) - 1)) & ~((2 * (sizeof(size_t))) - 1))) &&
((old_top)->size & 0x1) && ((unsigned long)old_end & pagemask) == 0)' failed.
Aborted (core dumped)

我认为一定有内存泄漏,所以我启动了 valgrind以帮助定位问题。输出结果让我目瞪口呆:
user@comp:~/Current/Working/Directory valgrind ./a.out 1000 
==4032== Memcheck, a memory error detector
==4032== Copyright (C) 2002-2012, and GNU GPL'd, by Julian Seward et al.
==4032== Using Valgrind-3.8.1 and LibVEX; rerun with -h for copyright info
==4032== Command: ./ans-0080 1000
==4032==
==4032== Invalid write of size 4
==4032== at 0x8048920: gatherSquares (prog.c:59)
==4032== by 0x80486C4: main (prog.c:36)
==4032== Address 0x427b288 is 0 bytes after a block of size 40 alloc'd
==4032== at 0x402C418: malloc (in /usr/lib/valgrind/vgpreload_memcheck-x86-linux.so)
==4032== by 0x804890F: gatherSquares (prog.c:55)
==4032== by 0x80486C4: main (prog.c:36)
==4032==
--4032-- VALGRIND INTERNAL ERROR: Valgrind received a signal 11 (SIGSEGV) - exiting
--4032-- si_code=1; Faulting address: 0x66656220; sp: 0x625b8a80

valgrind: the 'impossible' happened:
Killed by fatal signal
==4032== at 0x380DA208: ??? (in /usr/lib/valgrind/memcheck-x86-linux)
==4032== by 0x380DAAB1: ??? (in /usr/lib/valgrind/memcheck-x86-linux)
==4032== by 0x38054133: ??? (in /usr/lib/valgrind/memcheck-x86-linux)
==4032== by 0x38054206: ??? (in /usr/lib/valgrind/memcheck-x86-linux)
==4032== by 0x38052115: ??? (in /usr/lib/valgrind/memcheck-x86-linux)
==4032== by 0x20657360: ???

sched status:
running_tid=1

Thread 1: status = VgTs_Runnable
==4032== at 0x402C63E: realloc (in /usr/lib/valgrind/vgpreload_memcheck-x86-linux.so)
==4032== by 0x8048979: gatherSquares (prog.c:61)
==4032== by 0x80486C4: main (prog.c:36)

注意行 valgrind: the 'impossible' happened: !发生了什么不可能的事情?这是什么意思?

PS:
如果您知道该程序是为什么而编写的,请不要发布对搜索引擎索引的引用!

最佳答案

我怀疑这不是内存泄漏,而是您在分配的缓冲区开始之前或结束之后写入,从而覆盖了 malloc 用于维护其数据结构的数据,从而导致 malloc 失败。

我无法编译您的代码进行测试,但在快速目视检查时,这看起来很可疑(在gatherSquares() 中):

if(*count > size)
*arr = realloc(*arr, (size*=2) * sizeof **arr);

您需要根据 i 重新分配,而不是 *count 指向。

关于c - 不可能的事情发生了!这是什么意思?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19062015/

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