sql - 当一个行的结束时间是另一个行的开始时间时合并行 (Oracle)

Question

我似乎无法弄清楚这个查询。我需要将时间连续的状态行组合成一个状态。

这个问题与此处找到的问题类似，只是我使用的是 Oracle 10 而不是 SQL Server:Combine rows when the end time of one is the start time of another

示例数据:

name      start_inst         end_inst            code     subcode
Person1 9/12/2011 10:55 9/12/2011 11:49           161   50
Person1 9/12/2011 11:49 9/12/2011 11:55           107   28
Person1 9/12/2011 11:55 9/12/2011 12:07           161   50
Person1 9/12/2011 12:07 9/12/2011 12:26           161   50
Person1 9/12/2011 12:26 9/12/2011 12:57           161   71
Person1 9/12/2011 12:57 9/12/2011 13:07           161   71
Person1 9/12/2011 13:07 9/12/2011 13:20            52   50

我想得到以下输出:

name       start_inst       end_inst            code     subcode
Person1 9/12/2011 10:55     9/12/2011 11:49     161     50
Person1 9/12/2011 11:49     9/12/2011 11:55     107     28
Person1 9/12/2011 11:55     9/12/2011 12:26     161     50
Person1 9/12/2011 12:26     9/12/2011 13:07     161     71
Person1 9/12/2011 13:07     9/12/2011 13:20     52      50

下面是 SQL 示例:

CREATE TABLE Data (
    name varchar2(132 BYTE) not null,
    start_inst DATE not null,
    end_inst DATE not null,    
code number(3) not null,
subcode number(3) not null
);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 10:55','9/12/2011 11:49',161, 50);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 11:49','9/12/2011 11:55',107,28);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 11:55','9/12/2011 12:07',161,50);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 12:07','9/12/2011 12:26',161,50);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 12:26','9/12/2011 12:57',161,71);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 12:57','9/12/2011 13:07',161,71);
INSERT INTO Data(name,start_inst,end_inst, code, code2) VALUES('Person1','9/12/2011 13:07','9/12/2011 13:20',52,50);

提前致谢!

Answer 1

也许是这个？ (我没有 SQL 机器来运行它)

WITH
  sequenced_data AS
(
  SELECT
    ROW_NUMBER() OVER (PARTITION BY name                ORDER BY start_inst) NameSequenceID,
    ROW_NUMBER() OVER (PARTITION BY name, code, subcode ORDER BY start_inst) NameStateSequenceID,
    *
  FROM
    data
)
SELECT
  name,
  MIN(start_inst) start_inst,
  MAX(end_inst)   end_inst,
  code,
  subcode
FROM
  sequenced_data
GROUP BY
  name,
  code,
  subcode,
  NameSequenceID - NameStateSequenceID