python-3.x - 在 Python 中将请求发布到 Slack

Question

我正在编写一个脚本来读取两个 CSV 文件之间的差异。读出后，我应该使用 WebHook 将比较结果联系到松弛页面。我在发送 Post 方法时遇到困难。

slack 提供的链接生成 400 的响应在末尾使用/post 或 :8080 你会得到一个 200，但 slack 页面中没有弹出任何内容。

有什么想法或建议吗？

    def main():
    csvDiff()
    #print(l)
    post()

def csvDiff():
    f = open("new.csv")
    csv_f = csv.reader(f)
    old=set(pd.read_csv("old.csv", index_col=False, header=None)[0]) #reads the csv, takes only the first column and creates a set out of it.
    new=set(pd.read_csv("new.csv", index_col=False, header=None)[0]) #same here
    diff = new - old
    #Convert the diff set into a list
    diff=list(diff)
    #print(diff)
    #print(newConnections)
    for row in csv_f:
        if row[0] in diff:
            l.append(row)

def makeCsv():
        l = pd.to_csv

def post():
    url = 'whatever'
    payload={"text": "A very important thing has occurred! <https://alert-system.com/alerts/1234|Click here> for details!"}
    r = requests.post(url, data=json.dumps(l).encode('utf8'))
    print(r)

if __name__ == "__main__":
    main()

Answer 1

试试这一行:

r = requests.post(url, json=payload)