java - 如何使用此路径读取 xml 字符串值，如代码所示(getFilesDir().getAbsolutePath()+ File.separator + "test.xml")

Question

大家好，

我是 Android 新手。我正在使用 DOM 解析来读取 xml 字符串值。为此，我使用了以下代码，该代码将在给出异常之后获取根元素值，请解决此问题，

提前致谢，

XML 代码:

<?xml version='1.0' encoding='UTF-8' standalone='yes' ?>
<ChangePassword>
  <Oldpassword>23545565635354</Oldpassword>
  <Newpassword>addsffggfdsfdsfdfs </Newpassword>
</ChangePassword>

java代码:

   File file = new File(getFilesDir().getAbsolutePath()+ File.separator + "test.xml"); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
                      DocumentBuilder db = dbf.newDocumentBuilder();
                      Document doc = db.parse(file);
                      doc.getDocumentElement().normalize();
                      System.out.println("Root element " + doc.getDocumentElement().getNodeName());
                      NodeList nodeLst = doc.getElementsByTagName("ChangePassword");
                      System.out.println("Information of all entries");

                      for (int s = 0; s < nodeLst.getLength(); s++) {

                        Node fstNode = nodeLst.item(s); 

                        if (fstNode.getNodeType() == Node.ELEMENT_NODE)
                        {
                          Element fstElmnt = (Element) fstNode;

                          // Firstname
                          NodeList fstNmElmntLst = ((Document) fstElmnt).getElementsByTagName("Oldpassword");
                          Element fstNmElmnt = (Element) fstNmElmntLst.item(0);
                          NodeList fstNm = ((Node) fstNmElmnt).getChildNodes();
                          System.out.println("Old password : "  + ((Node) fstNm.item(0)).getNodeValue());

                          // Lastname
                          NodeList lstNmElmntLst = ((Document) fstElmnt).getElementsByTagName("Newpassword");
                          Element lstNmElmnt = (Element) lstNmElmntLst.item(0);
                          NodeList lstNm = ((Node) lstNmElmnt).getChildNodes();
                          System.out.println("Old password : " + ((Node) lstNm.item(0)).getNodeValue());

                          // Address
                          NodeList addrNmElmntLst = ((Document) fstElmnt).getElementsByTagName("Newpassword");
                          Element addrNmElmnt = (Element) addrNmElmntLst.item(0);
                          NodeList addrNm = ((Node) addrNmElmnt).getChildNodes();
                          System.out.println("Address : " + ((Node) addrNm.item(0)).getNodeValue());
                        }
                      }
                  } catch (Exception e) {
                      Log.e("Exception",e.toString());
                    //e.printStackTrace();
                  }

Answer 1

哇。 DOM 解析器代码非常丑陋。请只是try Simple XML instead 。看看你的代码可能是什么样的:

@Root(name = "ChangePassword")
public class PasswordChange {
   @Element(name = "Oldpassword")
   public String oldPassword;

   @Element(name = "Newpassword")
   public String newPassword;
}

这样就好多了。然后你可以说:

Serializer serial = new Persister();
PasswordChange pc = serial.read(PasswordChange.class, streamOrFileWithXML);

这就是全部内容了。不过，如果您想了解如何将其包含在 Android 中，请查看 look at my blog post .