java - 打乱数组列表后，如何在数组列表中跟踪正确答案？

Question

代码:

       private void getAnswers(int Type) {
    /* 
     * Getting answers here
     */
    //int randomValue = random(4);
    try { 
    String answers_list[][] = {
            {"Answer 1-1", "Answer 2-1", "Answer 3-1", "Answer 4-1"}, 
            {"Answer 1-2", "Answer 2-2", "Answer 3-2", "Answer 4-2"},
            {"Answer 1-3", "Answer 2-3", "Answer 3-3", "Answer 4-3"},
            {"Answer 1-4", "Answer 2-4", "Answer 3-4", "Answer 4-4"},
            {"Answer 1-5", "Answer 2-5", "Answer 3-5", "Answer 4-5"}} ;
    //answer1.setText(answers_list[Type][randomValue+1 > 3 ? (randomValue+0)-4 : randomValue+0]); 
    //answer2.setText(answers_list[Type][randomValue+2 > 3 ? (randomValue+1)-3 : randomValue+1]); 
    //answer3.setText(answers_list[Type][randomValue+3 > 3 ? (randomValue+2)-2 : randomValue+2]); 
    //answer4.setText(answers_list[Type][randomValue+0 > 3 ? (randomValue+3)-4 : randomValue+3]);
    Collections.shuffle(Arrays.asList(answers_list[Type]));
    answer1.setText(answers_list[Type][0]);
    answer2.setText(answers_list[Type][1]);
    answer3.setText(answers_list[Type][2]);
    answer4.setText(answers_list[Type][3]);
    /*for (int rows = 0; rows < answer&*list.length; rows++){
    for (int cols = 0; cols < answers_list[rows].length; cols++){   
      }
        }*/
    } catch(Exception ex){
    answer1.setText("Error "+ex);
    }



}

我想要“答案 1-1”、“答案 1-2”、“答案 1-3”、 “答案 1-4”、“答案 1-5” 是正确答案，我用它来检查答案是否正确......

switch(view.getId()){
    case R.id.button5:
        clicks++;
        if(clicks > 0)
        beginn.setText("Next");
        break;
    case R.id.button1:
        if(answer == 1)
        correct++;
        else
        correct--;
        break;
    case R.id.button2:
        if(answer == 2)
            correct++;
            else
            correct--;
        break;
    case R.id.button3:
        if(answer == 3)
            correct++;
            else
            correct--;
        break;
    case R.id.button4:
        if(answer == 4)
            correct++;
            else
            correct--;
        break;

基本上，我需要将我的 answer 整数设置为某个值，我该怎么做？

编辑:我知道它是 answer = number; ，但是什么数字？在我的数组列表被打乱后，如何检查它是否是“Answer 1-1”？不做类似的事情:

 if(answers_list[Type][0] == "Answer 1-1")
 answer = 1;
 else if(answers_list[Type][1] == "Answer 1-1")
 answer = 2;

Answer 1

我不会为此使用二维数组，而是使用一个类来保存问题字符串、错误答案字符串和正确答案字符串。此类可以有一个方法，该方法返回已随机化的潜在答案的字符串数组，并且可以知道哪一个是正确的。