hdl - 我的 DMux 4 方式有什么问题？

Question

看起来快要工作了，只是在第 7 行显然搞砸了？

/**
 * 4-way demultiplexor.
 * {a,b,c,d} = {in,0,0,0} if sel==00
 *             {0,in,0,0} if sel==01
 *             {0,0,in,0} if sel==10
 *             {0,0,0,in} if sel==11
 */


CHIP DMux4Way {
    IN in, sel[2];
    OUT a, b, c, d;

    PARTS:
    DMux(in = in, sel = sel[0], a = out1, b = out2);

    DMux(in = out1, sel = sel[1], a = a, b = b);
    DMux(in = out2, sel = sel[1], a = c, b = d);
}

我已经按如下方式实现了 DMux，并且我只是像使用一棵树一样使用它:

/**
 * Dmultiplexor.
 * {a,b} = {in,0} if sel==0
 *         {0,in} if sel==1
 */


CHIP DMux {
    IN in, sel;
    OUT a, b;

    PARTS:
    Not(in = sel, out = notsel);
    And(a = in, b = notsel, out = a);
    And(a = in, b = sel, out = b);
}

Answer 1

你的想法是对的!但您首先缩小了 sel[0] 的范围，而不是 sel[1]，后者对应于左列。

PS:我知道我迟到了

编辑:根据以下请求添加固定代码。感谢您的反馈

CHIP DMux4Way {
    IN in, sel[2];
    OUT a, b, c, d;

    PARTS:
    DMux(in = in, sel = sel[1], a = out1, b = out2);

    DMux(in = out1, sel = sel[0], a = a, b = b);
    DMux(in = out2, sel = sel[0], a = c, b = d);
}

在缩小真值表中引用左列的范围时(即 sel[1]；记住在计数时从右侧开始)，您可以有效地将选项拆分在中间