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r - 如何操作一列的两 block ?

转载 作者:行者123 更新时间:2023-12-02 08:06:16 25 4
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我正在处理一些遗传数据,但我的其中一个专栏不是我想要的格式。我不知道这里讨论了多少生物学,但我正在尝试修复我的氨基酸在我的数据中的显示方式。

氨基酸显然有一个名字,但它们也有一个 3 个字母的缩写和一个 1 个字母的缩写。我的数据包含 3 个字母形式的氨基酸,但我想将它们更改为 1 个字母的缩写。这是我的数据示例。

 chr location           effect   impact AA_change
1 12543 missense_variant MODERATE p.Ala12Val
1 52367 missense_variant MODERATE p.Leu54Pro
1 752347 missense_variant MODERATE p.Met99Ser
1 984645 missense_variant MODERATE p.Lys34Ile
1 989845 missense_variant MODERATE p.Arg4Cys
1 999854 missense_variant MODERATE p.His43Gly
1 999855 missense_variant MODERATE p.Glu14Phe

dat <- structure(list(chr = c(1L, 1L, 1L, 1L, 1L, 1L, 1L), location = c(12543L,
52367L, 752347L, 984645L, 989845L, 999854L, 999855L), effect = c("missense_variant",
"missense_variant", "missense_variant", "missense_variant", "missense_variant",
"missense_variant", "missense_variant"), impact = c("MODERATE",
"MODERATE", "MODERATE", "MODERATE", "MODERATE", "MODERATE", "MODERATE"
), AA_change = c("Ala12Val", "Leu54Pro", "Met99Ser", "Lys34Ile",
"Arg4Cys", "His43Gly", "Glu14Phe")), .Names = c("chr", "location",
"effect", "impact", "AA_change"), row.names = c(NA, -7L), class = "data.frame")

这是一个 3 字母氨基酸的列表,以及它们更好的缩写是什么。

  Ala == A
Arg == R
Asn == N
Asp == D
Cys == C
Glu == E
Gln == Q
Gly == G
His == H
Ile == I
Leu == L
Lys == K
Met == M
Phe == F
Pro == P
Ser == S
Thr == T
Trp == W
Tyr == Y
Val == V

我觉得有一个简单的功能可以做到这一点,但我正在努力解决如何做到这一点。我习惯于只更改专栏的一部分,而不是一次更改两件事。所以我想问的是我怎样才能改变这个

Ala12Val
Leu54Pro
Met99Ser
Lys34Ile
Arg4Cys
His43Gly
Glu14Phe

为此

A12V
L54P
M99S
K32I
R4C
E14F

这是可以做到的吗?

最佳答案

查找氨基酸,然后获取前 3 个字母的子串和映射,提取数字,后 3 个字母的子串和映射。然后粘贴在一起。

# lookup map
AAmap <- setNames(c("A","R","N","D","C","E","Q","G","H","I","L","K","M","F","P","S","T","W","Y","V"),
c("Ala","Arg","Asn","Asp","Cys","Glu","Gln","Gly","His","Ile","Leu","Lys","Met","Phe","Pro","Ser","Thr","Trp","Tyr","Val"))

# get first 3 map to AA, get digits, get last 3 map to AA
dat$AA_change_short <-
paste0(AAmap[ substr(dat$AA_change, 1, 3) ],
gsub("[^\\d]+", "", dat$AA_change, perl = TRUE),
AAmap[ substr(dat$AA_change, nchar(dat$AA_change) - 2, nchar(dat$AA_change)) ])

dat
# chr location effect impact AA_change AA_change_short
# 1 1 12543 missense_variant MODERATE Ala12Val A12V
# 2 1 52367 missense_variant MODERATE Leu54Pro L54P
# 3 1 752347 missense_variant MODERATE Met99Ser M99S
# 4 1 984645 missense_variant MODERATE Lys34Ile K34I
# 5 1 989845 missense_variant MODERATE Arg4Cys R4C
# 6 1 999854 missense_variant MODERATE His43Gly H43G
# 7 1 999855 missense_variant MODERATE Glu14Phe E14F

关于r - 如何操作一列的两 block ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51142998/

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