java - android sax xml 解析多个父级

Question

我正在尝试通过sax解析技术从xml页面解析数据。xml页面的结构是

<?xml version="1.0" encoding="UTF-8"?>
<news_magazine>
    <latest_news>
        <news>
            <category_id>5</category_id>
            <author>Super Admin</author>
        </news>
        <news>
            <category_id>6</category_id>
            <author>user</author>
        </news>
    </latest_news>
    <categories>
        <category>
            <category_id>5</category_id>
            <category_name>cricket</category_name>
        </category>
        <category>
            <category_id>5</category_id>
            <category_name>cricket</category_name>
        </category>
    </categories>
</news_magazine>

新闻标签和分类标签都包含分类id，如何分别获取分类id？

Answer 1

嘿，你可以用非常简单的方式做到这一点。只需维护一个额外的变量当您在解析器中放置条件时，当您获得任何“新闻”或“类别”标记时，而不是在 current_parent 中分配该标记。并且在比较标签“category_id”时还添加了 current_parent 的条件

public static String current_parent;
public void startElement(String namespaceURI, String localName, 
            String qName, Attributes atts) {
    if (localName.equals("news") {
          current_parent = "news";
        // Do your code with news.
        return;
    }
    else  if (localName.equals("category") {
          current_parent = "category";
        // Do your code with category.
        return;
    }
     else  if (localName.equals("category_id") {
         if(current_parent.equals("category")
            {
        // Do your code with category's category_id.
             }else if(current_parent.equals("news")
               {
        // Do your code with news's category_id.
             }
        return;
    }
}