java - Android 中的循环

Question

任何帮助将不胜感激。我正在尝试实现一个简单的数学游戏。我已经能够生成随机问题并能够验证答案，但我想将游戏限制为十个问题，并在最终问题后显示用户得分。我是一名新手程序员，据我了解，我需要某种形式的循环。任何代码示例或一般帮助/建议都很棒，谢谢。

@Override
public void onClick(View v){
switch(v.getId()){
case R.id.keypad_hash:

    checkAnswer();
    getQuestion();


    break;

case R.id.keypad_1:

    editText.append(String.valueOf(v.getTag()));

    break;


case R.id.keypad_2:

    editText.append(String.valueOf(v.getTag()));

    break;



case R.id.keypad_3:

    editText.append(String.valueOf(v.getTag()));

    break;

case R.id.keypad_4:

editText.append(String.valueOf(v.getTag()));

break;

case R.id.keypad_5:

editText.append(String.valueOf(v.getTag()));

break;

case R.id.keypad_6:

editText.append(String.valueOf(v.getTag()));

break;

case R.id.keypad_7:

editText.append(String.valueOf(v.getTag()));

break;

case R.id.keypad_8:

editText.append(String.valueOf(v.getTag()));

break;

case R.id.keypad_9:

editText.append(String.valueOf(v.getTag()));

break;
case R.id.keypad_0:

editText.append(String.valueOf(v.getTag()));

break;
case R.id.keypad_delete:

    if (editText.getText().length() > 0) {
        editText.getText().delete(editText.getText().length() - 1,
                editText.getText().length());
    }

break;

case R.id.keypad_minus:

editText.append(String.valueOf(v.getTag()));


break;

  } 
}

public void getQuestion(){

    random1 = (int)(Math.random()*100);
    random2 = (int)(Math.random()*10);

    int i1 = Min + (int)(Math.random() * ((Max - Min) + 1));
    for (int i = 0; i < 10; i++) {
    if(i1 == 1){
    question = (random1 + "+" + random2);
    correctAnswer = random1 + random2;
    editTextEquation.setText(question);
    }
    if(i1 == 2){
    question = (random1 + "-" +random2);
    correctAnswer = random1 - random2;
    editTextEquation.setText(question);

    }
    if(i1 == 3){
    question = random1 + "/" +random2;
    correctAnswer = random1 / random2;
    editTextEquation.setText(question);

    }
    if(i1 == 4){
    question = (random1 + "*" +random2);
    correctAnswer = random1 * random2;
    editTextEquation.setText(question);


    }
    }

    }




    public void checkAnswer(){
       int mm = 0;
        //answer = editText.getText().toString();
        mm = Integer.parseInt(editText.getText().toString());

        if (mm == correctAnswer){

          score++;
        scoredisplay.setText("" + score);


    }
        else {

        score--;
        scoredisplay.setText("" + score);
    }




 }


}

Answer 1

您可能不需要按照构建方式构建循环。

this.counter = 10;

...

case R.id.keypad_hash:
  checkAnswer();
  this.counter--;
  if( this.counter > 0 ){
    getQuestion();
  } else {
    scoreText.setText(score);
  }
  break;