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tsql - 将日期范围转换为每天记录的 SQL 查询

转载 作者:行者123 更新时间:2023-12-02 07:48:18 24 4
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要求

  1. 我有一个数据表,用于保存日期范围内的数据。
  2. 允许每条记录与之前的记录重叠(记录有一个 CreatedOn datetime 列)。
  3. 如果需要,新记录可以定义自己的日期范围,因此可以与多个旧记录重叠。
  4. 每条新的重叠记录都会覆盖它重叠的旧记录的设置。

结果集

我需要获取的是获取使用记录重叠的任何日期范围内的每日数据。它应该每天返回一条记录,其中包含该特定日期的相应数据。

要将范围转换为天数,我正在考虑 numbers/dates table 和用户定义函数 (UDF) 来获取范围内每一天的数据,但我想知道是否还有其他方法(如更好* 甚至更快)这样做的方式,因为我使用的是最新的 SQL Server 2008 R2。

存储的数据

想象一下我存储的数据是这样的

ID | RangeFrom | RangeTo  | Starts | Ends  | CreatedOn (not providing data)
---|-----------|----------|--------|-------|-----------
1 | 20110101 | 20110331 | 07:00 | 15:00
2 | 20110401 | 20110531 | 08:00 | 16:00
3 | 20110301 | 20110430 | 06:00 | 14:00 <- overrides both partially

结果

如果我想获取从 2011 年 1 月 1 日到 2001 年 5 月 31 日的数据,结果表应该如下所示(省略了明显的行):

DayDate | Starts | Ends
--------|--------|------
20110101| 07:00 | 15:00 <- defined by record ID = 1
20110102| 07:00 | 15:00 <- defined by record ID = 1
... many rows omitted for obvious reasons
20110301| 06:00 | 14:00 <- defined by record ID = 3
20110302| 06:00 | 14:00 <- defined by record ID = 3
... many rows omitted for obvious reasons
20110501| 08:00 | 16:00 <- defined by record ID = 2
20110502| 08:00 | 16:00 <- defined by record ID = 2
... many rows omitted for obvious reasons
20110531| 08:00 | 16:00 <- defined by record ID = 2

最佳答案

实际上,由于您正在处理日期,日历表会更有帮助。

Declare @StartDate date
Declare @EndDate date

;With Calendar As
(
Select @StartDate As [Date]
Union All
Select DateAdd(d,1,[Date])
From Calendar
Where [Date] < @EndDate
)
Select ...
From Calendar
Left Join MyTable
On Calendar.[Date] Between MyTable.Start And MyTable.End
Option ( Maxrecursion 0 );

添加

在您的原始帖子中遗漏了有关王牌规则的部分:

Set DateFormat MDY;
Declare @StartDate date = '20110101';
Declare @EndDate date = '20110501';

-- This first CTE is obviously to represent
-- the source table
With SampleData As
(
Select 1 As Id
, Cast('20110101' As date) As RangeFrom
, Cast('20110331' As date) As RangeTo
, Cast('07:00' As time) As Starts
, Cast('15:00' As time) As Ends
, CURRENT_TIMESTAMP As CreatedOn
Union All Select 2, '20110401', '20110531', '08:00', '16:00', DateAdd(s,1,CURRENT_TIMESTAMP )
Union All Select 3, '20110301', '20110430', '06:00', '14:00', DateAdd(s,2,CURRENT_TIMESTAMP )
)
, Calendar As
(
Select @StartDate As [Date]
Union All
Select DateAdd(d,1,[Date])
From Calendar
Where [Date] < @EndDate
)
, RankedData As
(
Select C.[Date]
, S.Id
, S.RangeFrom, S.RangeTo, S.Starts, S.Ends
, Row_Number() Over( Partition By C.[Date] Order By S.CreatedOn Desc ) As Num
From Calendar As C
Join SampleData As S
On C.[Date] Between S.RangeFrom And S.RangeTo
)
Select [Date], Id, RangeFrom, RangeTo, Starts, Ends
From RankedData
Where Num = 1
Option ( Maxrecursion 0 );

简而言之,我优先选择与同一日期重叠的较新行对所有样本数据进行排名。

关于tsql - 将日期范围转换为每天记录的 SQL 查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5363003/

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