sql - 在 SQL Server 中选择文字作为表数据

Question

考虑表 Address ，其中包含 Country、State 和其他数据字段。我想获取除 Country,State 组合为 (US, IL), (US,LA), (IND,DEL) 之外的所有记录

查询就像

Select * from Address a 
where not exists 
(
   select Country,State 
   (select 'US' as Country, 'IL' as State 
     union
   select 'US' as Country, 'LA' as State 
     union
    select 'IND' as Country, 'DEL' as State 
  ) e
 where e.Country != a.Country and e.State != a.state
)

如何轻松实现(用简单的子查询替换国家，联合的状态组合)？由于总数据不是很大，我现在最不关心性能。

我知道我可以创建表变量，使用 insert into 语法添加所有文字组合，并使用表变量表示不存在，但我觉得这对于小需求(不存在于 2 个变量)来说有点过分了。

Answer 1

看起来您的查询试图这样做:

select * 
from Address a 
where not exists (
                 select *
                 from (
                      select 'US' as Country, 'IL' as State union all
                      select 'US' as Country, 'LA' as State union all
                      select 'IND' as Country, 'DEL' as State 
                      ) e
                 where e.Country = a.Country and 
                       e.State = a.State
                 )

或者您无法使用派生表并仍然获得相同的结果

select *
from Address as a
where not (
          a.Country = 'US' and a.State = 'IL' or
          a.Country = 'US' and a.State = 'LA' or
          a.Country = 'IND' and a.State = 'DEL'
          )