php - 如何在默认情况下选中复选框并从 Laravel 中的数据库中检索旧值

Question

我有一个复选框，我想让我的复选框默认选中，如果用户取消选中复选框并保存表单，我需要在检索或编辑表单数据时取消选中该复选框。

我的查看页面

<div class="form-group {{ $errors->has('active') ? 'error' : '' }}">
                <label for="active" class="col-md-3 control-label">@lang('admin/assetdetails/form.active')</label>
                     <div class="controls col-md-7">
                            {{ Form::checkbox('active', 1, Input::old('active', $assetdetail->active), array('class'=>'isnesdbox')) }}
                            {{ $errors->first('active', '<span class="alert-msg"><i class="icon-remove-sign"></i> :message</span>') }}
                     </div>
            </div>

给这个正确地从数据库中带回旧数据，但我无法将我的复选框选中为默认

Controller :

public function postEdit($assetdetailId = null)
    {
        // Check if the location exists
        if (is_null($assetdetail = Assetdetail::find($assetdetailId)))
        {
            // Redirect to the blogs management page
            return Redirect::to('admin/settings/assetdetails')->with('error', Lang::get('admin/assetdetails/message.does_not_exist'));
        }



        // get the POST data
        $new = Input::all();

        // attempt validation
        if ($assetdetail->validate($new))
        {

            // Update the location data

            $assetdetail ->asset_number             = e(Input::get('asset_number'));
            $assetdetail ->location_id              = e(Input::get('location_id'));
            $assetdetail ->assign_to                = e(Input::get('assign_to'));
            $assetdetail ->asset_type_id            = e(Input::get('asset_type_id'));
            $assetdetail ->nesd                     = e(Input::get('nesd'));
            $assetdetail ->active                   = e(Input::get('active'));
            $assetdetail ->shift                    = e(Input::get('shift'));
            $assetdetail ->supplier_name            = e(Input::get('supplier_name'));
            $assetdetail ->description              = e(Input::get('description'));
            $assetdetail ->dateof_purchase          = e(Input::get('dateof_purchase'));
            $assetdetail ->label_number             = e(Input::get('label_number'));
            $assetdetail ->purchase_price           = e(Input::get('purchase_price'));
            $assetdetail ->dateof_disposed          = e(Input::get('dateof_disposed'));
            $assetdetail ->depreciation_type        = e(Input::get('depreciation_type'));
            $assetdetail ->salvage_value            = e(Input::get('salvage_value'));
            $assetdetail ->asset_life               = e(Input::get('asset_life'));




            // Was the asset created?
            if($assetdetail->save())
            {
                // Redirect to the saved location page
                return Redirect::to("admin/settings/assetdetails/$assetdetailId/edit")->with('success', Lang::get('admin/assetdetails/message.update.success'));
            }
        }
        else
        {
            // failure
            $errors = $assetdetail->errors();
            return Redirect::back()->withInput()->withErrors($errors);
        }

        // Redirect to the location management page
        return Redirect::to("admin/settings/assetdetails/$assetdetailId/edit")->with('error', Lang::get('admin/assetdetails/message.update.error'));

    }

我试过

{{ Form::checkbox('active', 1, true, Input::old('active', $assetdetail->active), array('class'=>'isnesdbox')) }}

但我得到了以下错误

不能将标量值用作数组

我也试过这个

<input class="col-md-1 controls isnesdbox" type="checkbox" name="active" checked id="active" value="1" {{ $assetdetail->active === '1' ? 'checked' : '' }} />

请帮助我实现这一目标
注意:iam 使用 mysql 数据库，iam 使用的数据库类型是 bit，它根据用户输入存储 0 和 1。

Answer 1

由于谷歌显然仍然认为这个答案是相关的，这里是 Laravel 5.8 的更新答案:

<input type="checkbox" value="true" name="notify" @if(!old() || old('notify') == 'true') checked="checked" @endif />