java - 检查 ace 是否存在以及点数是否 >21

Question

在我的二十一点程序中，我有:

Card c = dealCard(deck); //deals the card
updatePoints(players[i], c); // calls updatePoints below. 

updatePoints 函数如下所示:

public static void updatePoints(Player player,  Card c){

        int point = c.getValue();
        if(player.getPoints() + point >21 && (player.ace1 == 11 || player.ace2 == 11 || player.ace3 == 11 || player.ace4 == 11)){
            player.points -= 10;
            player.setPoints(point);
            if (player.ace1 == 11){
                player.ace1 = 1;
            }else if(player.ace2 == 11){
                player.ace2 = 1;
            }else if(player.ace3 == 11){
                player.ace3 = 1;
            }else if (player.ace4 == 11){
                player.ace4 = 1;
            }
        }
        if (point == 1){
            //default value for player.ace1 .. player.ace4 is 0


            if(player.ace1 == 0){
                player.ace1 = 11;
                player.setPoints(11);
            }else if (player.ace2 == 0){
                player.ace2 = 11;
                player.setPoints(11);
            }else if (player.ace3 == 0){
                player.ace3 = 11;
                player.setPoints(11);
            }else if(player.ace4 == 0){
                player.ace4 = 11;
                player.setPoints(11);
            }

        }else{
            player.setPoints(point);
        }
        return;
    }

出于某种原因，当点数超过 21 时，这不会改变 ace 值，也不会调整 ace。任何帮助将不胜感激。谢谢

Answer 1

你的代码看起来太复杂了。无需为每个 A 分配一个变量，只需保留未减少到 1 的 A 数量计数即可:

private int fullAceCount;

更新假设 A 为 11，同时也更新 A 计数:

if (points == 11) { // if it's an ace
    fullAceCount++; // save it for later deduction
}

然后更新任何卡后，检查是否需要扣除10

if (total > 21 && fullAceCount > 0) {
    total =- 10;
    fullAceCount--; // record that you've used up one of your aces
}

你就完成了。