java - 使用数组来决定谁是活跃玩家(回合制猜谜游戏)

Question

我正在使用一种方法(如下所示)，该方法允许我输入玩家数量以及每个玩家的名称。有没有办法让我使用这个数组来决定谁是活跃玩家？ (回合制猜谜游戏)。如果你能给我指出正确的方向就好了。

public class Program {
     String[] playerList;
     int playersAmount = 0;

      public void inputPlayers() {
          playersAmount = Input.readInt();
          playerList= new String[playersAmount];
          for (int g = 0; g < playersAmount; g++) {
              String namePlayer = "player " + (g+1);
              playerList [g] = namePlayer;
          }
      }
 }

Answer 1

你应该仔细看看我关于更改玩家编号的问题。我认为这正是您正在寻找的(或类似的东西):Java: Changing Player Number

本质上，我使用了一个 boolean 数组来跟踪谁仍在玩，其中数组索引对应于玩家编号a[0] =玩家0，a[1] =玩家1等。如果玩家被淘汰标记相应的索引为 false: a[i] = false; 然后您可以使用以下方法(取 self 的问题)将玩家编号切换到下一个仍在玩的玩家:

public static int switchPlayer(int currentPlayer, boolean[] playerList) {
    // if the current player + 1 = length (size) of array,
    // start back at the beginning and find the first player still playing
    if(currentPlayer + 1 == playerList.length) {
        for(int i = 0; i < playerList.length; i++) {
            if(playerList[i] == true) {    // if player is still in the game
                currentPlayer = i;         // currentPlayer = current index of array
                break;
            }
        }
    }
    // otherwise the current player number + 1 is not at the end of the array
    // i.e. it is less than the length (size) of the array, so find the next player
    // still playing
    else {
        for(int i = (currentPlayer+1); i < playerList.length; i++) {
            if(playerList[i] == true) {
                currentPlayer = i;
                break;
            }
        }
    }
    return currentPlayer;
}

如果您对我的代码等有任何疑问，请告诉我。