javascript - 如何使用JavaScript过滤JSON

Question

我需要根据其值过滤一个巨大的JSON文件。

这是我的JSON代码(这是我的JSON对象的一部分，实际上，它有1000多个)。

var jsonObject = [  
   {  
      "UserId":10259,
      "FullName":"hello world",
      "CustomerId":"10165"
   },
   {  
      "UserId":10405,
      "FullName":"test value",
      "CustomerId":"10261"
   },
   {  
      "UserId":10400,
      "FullName":"mark ant",
      "CustomerId":"10161"
   },
   {  
      "UserId":16224,
      "FullName":"jhon cena",
      "CustomerId":""
   },
   {  
      "UserId":10416,
      "FullName":"shoze ahh",
      "CustomerId":"1"
   },
   {  
      "UserId":10244,
      "FullName":"kajal man",
      "CustomerId":"10"
   }
];

为了过滤上述JSON对象，我使用了以下过滤器功能。

function usersBasedOnIDs(CustomerIds) {
    if (CustomerIds == "") {
        console.log(jsonObject);
    } else if (CustomerIds == "9999xx") {

        let result = jsonObject.filter(c => c.CustomerId == "");
        console.log(result);
    } else {
        let result = jsonObject.filter(c => c.CustomerId != "" && CustomerIds.includes(c.CustomerId));
        console.log(result);
    }   
}

我如何调用该函数

usersBasedOnIDs("");
usersBasedOnIDs("10261,10165");
usersBasedOnIDs("9999xx"); 

我的代码有几个问题，

此功能不适用于IE 11早期版本

还有另一件事是，当我将函数调用为usersBasedOnIDs("10261,10165");或usersBasedOnIDs("10261");时，其返回以下JSON输出
{UserId: 10405, FullName: "test value", CustomerId: "10261"}
{UserId: 10416, FullName: "shoze ahh", CustomerId: "1"}
{UserId: 10244, FullName: "kajal man", CustomerId: "10"}

但是我的期望是，只有这个

{UserId: 10405, FullName: "test value", CustomerId: "10261"}

怎样才能更改功能以避免 这两个问题

Answer 1

因此，这是基于@adiga答案的IE 11的完整答案。将箭头功能更改为普通功能，并使用 Array.indexOf 而不是includes。

const array = [
  { UserId: 10259, FullName: "hello world", CustomerId: "10165" },
  { UserId: 10405, FullName: "test value", CustomerId: "10261" },
  { UserId: 10400, FullName: "mark ant", CustomerId: "10161" },
  { UserId: 16224, FullName: "jhon cena", CustomerId: "" },
  { UserId: 10416, FullName: "shoze ahh", CustomerId: "1" },
  { UserId: 10244, FullName: "kajal man", CustomerId: "10" }
];

function usersBasedOnIDs(CustomerIds) {
  if (CustomerIds === "") return array;

  if (CustomerIds == "9999xx") {
    return array.filter(function(c) {
      return c.CustomerId == "";
    });
  }

  const ids = CustomerIds.split(",");
  return array.filter(function(c) {
    return c.CustomerId !== "" && ids.indexOf(c.CustomerId) > -1;
  });
}

console.log(usersBasedOnIDs("10261,10165"))