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java - 显示 JTable 中列表的下一行

转载 作者:行者123 更新时间:2023-12-02 07:16:48 25 4
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我将尝试尽可能彻底地解释我正在尝试做的事情,因为我对用户界面非常陌生。我有一个字符串列表,我们称之为 user_decide,其中包含不同数量的元素。例如

1st Row [192, 495, 393, 399]
2nd Row [384, 493, 945, 559, 485]

这些数字代表一些数组的索引,例如

Name[192] = "John", Name[495] = "Mary" 
Surname[192] = "Pap", Surname[495] = "Black"

我正在尝试制作一个具有上一个和下一个按钮以及 JTable 的 UI。

第一次,我的用户界面将显示

1st Column 2nd Column 3rd Column 4th Column 5th Column
Name John Mary etc..
Surname Pap Black

当我按“下一步”时,它将显示下一行:

1st Column 2nd Column    3rd Column    4th Column    5th Column 6th Column
Name Name[384] Name[493] Name[945] etc...
Surname Surname[384] Surname[493] Surname[945]

到目前为止,我所做的是一个包含大量 JTable 的框架。

JPanel panel = new JPanel();
int cols = 0;
Iterator<String> iterator = user_decide.iterator();
while (iterator.hasNext())
{
String con = iterator.next();
con = con.replaceAll("\\s", "").replaceAll("\\[", "").replaceAll("\\]", "");
String conv [] = con.split("\\,");
// It can be used for the "for-statement"
cols = conv.length;

List<String> column = new ArrayList<String>();
// Giving the name of the columns
for(int i = 0; i < cols + 1; i ++)
{
if (i == 0) column.add("");
else column.add("Column #" + i);
}
// Setting the jtable with a specific number of columns
String[] column_names = column.toArray(new String[column.size()]);
tableModel = new DefaultTableModel( 17, cols);
tableModel.setColumnIdentifiers(column_names);
JTable table = new JTable(tableModel);
// HERE I AM GOING TO PLACE MY DATA AFTERWARDS
SetData(table, "Name",0,0);
SetData(table, "Surname",1,0);


panel.add(new JScrollPane(table,
JScrollPane.VERTICAL_SCROLLBAR_ALWAYS,
JScrollPane.HORIZONTAL_SCROLLBAR_ALWAYS));
}
JFrame frame = new JFrame("Results");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setBounds(200, 200, 600, 400);
frame.add(new JScrollPane(panel,
JScrollPane.VERTICAL_SCROLLBAR_ALWAYS,
JScrollPane.HORIZONTAL_SCROLLBAR_ALWAYS));

frame.add(panel, BorderLayout.CENTER);
frame.setVisible(true);
}

public void SetData(JTable table, Object obj, int row_index, int col_index){
table.getModel().setValueAt(obj,row_index,col_index);
}

当我尝试使用一个将所有数据存储在一行中的表时,我有这个下一个按钮。

JPanel navigation = new JPanel(
new FlowLayout(FlowLayout.CENTER));
JButton next = new JButton("NEXT");
next.addActionListener( new ActionListener(){
public void actionPerformed(ActionEvent ae) {
int height = table.getRowHeight()*(rows-1);
JScrollBar bar = scrollPane.getVerticalScrollBar();
bar.setValue( bar.getValue()+height );
}
} );

如果有任何帮助,我将不胜感激。非常感谢您阅读本文。

最佳答案

public class SwitchTableModel extends AbstractTableModel {
private final String [] name = new String [] {"Alice", "Bob", "John", "Mary"};
private final String [] surname = new String [] {"Green", "Red", "Brown", "Grey"};

private final int [][] data = new int [][] {
new int [] {1, 3, 2},
new int [] {0, 2, 1, 3},
new int [] {0, 3},
new int [] {0, 1, 2, 3}
};

private int position = 0;

@Override
public int getRowCount() {
return 2;
}

@Override
public int getColumnCount() {
return data [position].length + 1;
}

@Override
public Object getValueAt(int rowIndex, int columnIndex) {
switch (rowIndex)
{
case 0:
return columnIndex == 0 ? "Name" : name [data [position][columnIndex - 1]];
case 1:
return columnIndex == 0 ? "Surname" : surname [data [position][columnIndex - 1]];
default:
throw new Error ();
}
}

public void previous ()
{
position -= 1;
if (position < 0) position = data.length - 1;

fireTableStructureChanged();
}

public void next ()
{
position += 1;
if (position >= data.length) position = 0;

fireTableStructureChanged();
}

public static void main(String[] args) {
final SwitchTableModel model = new SwitchTableModel();

Box toolbar = Box.createHorizontalBox();
toolbar.add (new JButton (new AbstractAction("Previous") {
@Override
public void actionPerformed(ActionEvent e) {
model.previous ();
}
}));
toolbar.add (Box.createHorizontalGlue());
toolbar.add (new JButton (new AbstractAction("Next") {

@Override
public void actionPerformed(ActionEvent e) {
model.next ();
}
}));

JTable table = new JTable(model);

JFrame frame = new JFrame ();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.getContentPane().setLayout(new BorderLayout());
frame.getContentPane().add (toolbar, BorderLayout.NORTH);
frame.getContentPane().add (
new JScrollPane(
table,
JScrollPane.VERTICAL_SCROLLBAR_ALWAYS,
JScrollPane.HORIZONTAL_SCROLLBAR_AS_NEEDED),
BorderLayout.CENTER);
frame.pack();
frame.setVisible(true);
}
}

关于java - 显示 JTable 中列表的下一行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14833607/

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