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xslt-2.0 - 为什么 Saxon 将结果文档 URI 评估为相同?

转载 作者:行者123 更新时间:2023-12-02 07:13:47 24 4
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我的 XSL 源文件是这样的

<Topology>
<Environment>
<Id>test</Id>
<Machines>
<Machine>
<Id>machine1</Id>
<modules>
<module>m1</module>
<module>m2</module>
</modules>
</Machine>
</Machines>
</Environment>
<Environment>
<Id>production</Id>
<Machines>
<Machine>
<Id>machine1</Id>
<modules>
<module>m1</module>
<module>m2</module>
</modules>
</Machine>
<Machine>
<Id>machine2</Id>
<modules>
<module>m3</module>
<module>m4</module>
</modules>
</Machine>
</Machines>
</Environment>
</Topology>

我想为每台机器创建一个结果文档,所以我使用以下样式表,将 modelDir 作为结果文档的路径作为参数。

<xsl:output method="xml" version="1.0" encoding="UTF-8" 
indent="yes" name="myXML" doctype-system="http://java.sun.com/dtd/properties.dtd"/>

<xsl:template match="/">
<xsl:for-each-group select="/Topology/Environment/Machines/Machine" group-by="Id">

<xsl:variable name="machine" select="Id"/>
<xsl:variable name="filename" select="concat($modelDir,$machine,'.xml')" />

<xsl:message terminate="no">Writing machine description to <xsl:value-of select="$filename"/></xsl:message>

<xsl:result-document href="$filename" format="myXML">

<xsl:variable name="currentMachine" select="Id"/>
<xsl:for-each select="current-group()/LogicalHosts/LogicalHost">
<xsl:variable name="environment" select="normalize-space(../../../../Id)"/>
<xsl:message terminate="no">Module <xsl:value-of select="."/> for <xsl:value-of select="$environment"/></xsl:message>
</xsl:for-each>

</xsl:result-document>

</xsl:for-each-group>
</xsl:template>

正如我的消息所显示的那样,这似乎工作正常 - 如果 saxon 不会将结果文档的 URI 评估为相同并因此给出以下输出。

Writing machine description to target/build/model/m1.xml
Module m1 for test
Module m2 for test
Module m1 for production
Module m2 for production
Writing machine description to target/build/model/m2.xml
Error at xsl:result-document on line 29 of file:/C:/Projekte/.../machine.xsl:
XTDE1490: Cannot write more than one result document to the same URI, or write to a URI
that has been read:
file:/C:/Projekte/.../$filename
file:/C:/Projekte/.../machine.xsl(29,-1) : here Cannot write more than one result document to the same URI, or write to a URI that has been read: file:/C:/Projekte/.../$filename
; SystemID: file:/C:/Projekte/.../machine.xsl; Line#: 29; Column#: -1
net.sf.saxon.trans.DynamicError: Cannot write more than one result document to the same URI, or write to a URI that has been read: file:/C:/Projekte/.../$filename
at net.sf.saxon.instruct.ResultDocument.processLeavingTail(ResultDocument.java:300)
at net.sf.saxon.instruct.Block.processLeavingTail(Block.java:365)
at net.sf.saxon.instruct.Instruction.process(Instruction.java:91)

关于如何解决这个问题有什么想法吗?

最佳答案

您正在为 @file 指定一个变量 $filename,但没有包装在 {} 中,因此它正在评估它作为每次都是字符串“$filename”(这是相同的 URI,因此是错误)。

您需要它来评估为 Attribute Value Template .

<xsl:result-document href="{$filename}" format="myXML">

关于xslt-2.0 - 为什么 Saxon 将结果文档 URI 评估为相同?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2974040/

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