asp.net-mvc - 如何将数据传递给 mvc asp.net 中的 View ？

Question

让我先问这个问题。

调用加载要在 View 上显示的值列表的函数的正确位置在哪里？

我创建了一个这样的 Controller

public ActionResult Create()
{
    SeaModel newSea = new SeaModel();

    return View("Season/CreateSea", newSea);
}

//I not quite sure if this should go here or in another place
partial class seaDataContext
{
    public List<string> getSeaSettings()
    {
        var seaSettings = from p in settings
                          where p.setting == "periods"
                          select p.value;

        return seaSettings.ToList<string>();                              
    }
}

模型是这样的

public class SeaModel
{
    [Required(ErrorMessage="*")]
    [Display(Name = "Period Name")]
    public string periods { get; set; }    
}

创建一个像这样的 View

  @using (Html.BeginForm()) {
        @Html.ValidationSummary(true, "Please correct the following errors.")

        <fieldset>
            <legend>Fields</legend>

            <div class="editor-label">
                @Html.LabelFor(model => model.periods)
            </div>
            <div class="editor-field">
                @Html.Select(model => model.periods, ****My doubt comes here****)
                @Html.ValidationMessageFor(model => model.periods)
            </div>

            <p>
                <input type="submit" value="Create" />
            </p>
        </fieldset>

    }

那么，如何以及在何处将 getSeaSettings() 的返回值传递给 View ？

谢谢

Answer 1

最佳做法是在您的模型中为此下拉列表创建一个选择列表。

但是您也可以使用更简单的选项:使用 ViewData

 public ActionResult Create()
 {
     SeaModel newSea = new SeaModel();

     ViewData["myDropDown"] = new SelectList(listOfObjects, "valueOfTheObjectLikeID", "NameYouWantToShowInDropdown");

     return View("Season/CreateSea", newSea);
 }

然后:

@Html.Select(model => model.periods, ViewData["myDropDown"] as SelectList)

如果验证失败，请不要忘记在 [HttpPost] 方法中也填写 View 数据，以便重建下拉列表。