java - 如何在匿名线程中声明异常？

Question

InputStream in = ClientSocket.getInputStream();
new Thread()
{
    public void run() {
        while (true)
        {
            int i = in.read();
            handleInput(i);
        }
    }
}.start();

我正在使用这段代码在套接字上监听新数据并得到:

FaceNetChat.java:37: unreported exception java.io.IOException; must be caught or declared to be thrown
                int i = in.read();
                               ^

当我在“run()”之后添加“throws IOException”时，我得到:

FaceNetChat.java:34: run() in  cannot implement run() in java.lang.Runnable; overridden method does not throw java.io.IOException
        public void run() throws IOException {
                    ^

这可能很简单，但我不知所措。我如何通过此考试？

Answer 1

您不能覆盖 Runnable.run() 的接口(interface)这不会引发异常。您必须改为在 run 方法中处理异常。

try {
  int i = in.read();
} catch (IOException e) {
  // do something that makes sense for your application
}