c - C 中的返回值函数

Question

您好，我正在开发一个生成主代码的快速程序，用户必须猜测代码。在检查用户的猜测时，我使用 2 个函数，一个用于精确匹配，另一个用于接近匹配(他们得到的数字在主代码中但不在正确的位置)

例。主密码 1 2 3 4

用户 2 3 2 4 输出应该显示用户有 2 个接近匹配和 1 个完全匹配。我无法理解如何正确返回 int。

当我尝试在 Main 中打印它们时，我的输出只显示了 exactMatch 和 closeMatch 的默认值。任何见解将不胜感激。谢谢。

 #include<stdio.h>
 #include<math.h>
 #include<stdlib.h>
 #include<time.h>
 #define CODELENGTH 4
 #define NUMSYMBOLS 6


 int MasterCode[4];
 int guess[ 4 ];
 int exactMatch;
 int closeMatch=0;

 void genCode (int MasterCode[])
{
int i=0;
int k;
while (i < CODELENGTH){

MasterCode[i] =rand() %NUMSYMBOLS +1;
    i++;

}//end while loop.
for ( k = 0 ; k < 4; k++ ) {
    printf( "%d ", MasterCode[ k ] );
}

printf( "\n" );
}





 void getGuess (int guess[])
{

int number = 0;

printf( "Please enter your list of 4 numbers between 1 and 6: " );
int j;
int k;
for ( j = 0 ; j < 4; j++ ) {
    scanf( "%d", &number );
    guess[ j ] = number;
}

printf( "Your array has these values: " );

for ( k = 0 ; k < 4; k++ ) {
    printf( "%d ", guess[ k ] );
}

printf( "\n" );
 }




 int main (int argc, char **argv)
 {
srand ( time(NULL) );

genCode(MasterCode);
getGuess(guess);
checkExactMatches(MasterCode, guess, exactMatch);
checkCloseMatches(MasterCode, guess, closeMatch);
printf("%d = Ending exactMatches \n", exactMatch);
printf("%d  = Ending closeMatches \n", closeMatch);





 }
 int checkExactMatches (int MasterCode[], int guess[], int exactMatch )
  {
int woot;
for(woot=0; woot<4; woot++){


        if (MasterCode[woot] == guess[woot]){
            printf("Exact Match found \n");
            exactMatch ++;
            printf( "%d = Guess \n" , guess[ woot ]);
            printf( "%d = MasterCode \n", MasterCode[ woot ]);
            printf("%d = exactMatch \n", exactMatch);

        }// end if

        if (MasterCode[woot] != guess[woot])
            printf("No EXACT match \n");


}//end for loop

return exactMatch;
 } // end checkExactMatches



 int checkCloseMatches (int MasterCode[], int guess[], int closeMatch )
  {
int k;
int j;
for(k=0; k<4; k++){

    for (j=0; j<4; j++) {


        if (MasterCode[k] == guess[j]){
    printf("CLOSE Match found \n");
    closeMatch ++;
    printf( "%d = Guess \n" , guess[ j ]);
    printf( "%d = MasterCode \n \n", MasterCode[ k ]);
    printf("%d = closeMatch \n \n", closeMatch);

}// end if

if (MasterCode[k] != guess[j])
    printf("No CLOSE match \n");


    }//end nested for loop
}//end for loop

return closeMatch;
 } // end checkCloseMatches

Answer 1

获取函数的返回值其实很简单，基本上和给变量赋值是一样的。在您的情况下，语法将是这样的:

int result = checkExactMatches(MasterCode, guess, exactMatch);

result 现在将保存函数返回的值。