regex - 清空 $1 和 $2 值 Regex Perl

Question

我有以下代码:

my $sDatabase = "abc_def:xyz_comp.";
if ($sDatabase =~ m/^(\w)*\:(\w*)\_em\.$/)
{
    print "$1\:$2\.\n";
}
else
{
    print "$1\:$2\_em\.\n";
}

但我得到的是空的 $1 和 $2。输出是:

Use of uninitialized value in concatenation (.) or string at new_mscn_iden_parse.pl line 187.
Use of uninitialized value in concatenation (.) or string at new_mscn_iden_parse.pl line 187.
:_em.

Answer 1

这段代码会做你想做的事

my $sDatabase = "abc_def:xyz_comp.";

$sDatabase =~ m/^(\w+):(\w+?)(_em)?\.$/ or die "Invalid data";
if ($3) {
  print "$1:$2.\n";
}
else {
  print "$1:$2_em.\n";
}