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oracle - 安全的 INTERVAL 算术

转载 作者:行者123 更新时间:2023-12-02 07:03:35 33 4
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此查询有效,没有错误

select add_months(date '2011-01-31', 1) from dual;

,而这个:

select date '2011-01-31' + interval '1' month from dual;

返回

ORA-01839: date not valid for month specified

那么有没有安全的方法可以使用INTERVAL文字添加间隔?

最佳答案

这遵循 ANSI 指定的向日期添加 INTERVAL 的行为1。这也被记录在案 here :

When interval calculations return a datetime value, the result must be an actual datetime value or the database returns an error. For example, the next two statements return errors:

SELECT TO_DATE('31-AUG-2004','DD-MON-YYYY') + TO_YMINTERVAL('0-1') FROM DUAL;

SELECT TO_DATE('29-FEB-2004','DD-MON-YYYY') + TO_YMINTERVAL('1-0') FROM DUAL;

函数ADD_MONTHS另一方面,如果结果月份的天数较少,则只会给您该月的最后一天 - 我相信这个函数是为了解决这个问题而创建的。

<小时/>

1 http://www.contrib.andrew.cmu.edu/~shadow/sql/sql1992.txt

b) Arithmetic is performed so as to maintain the integrity of
the datetime data type that is the result of the <datetime
value expression>. This may involve carry from or to the
immediately next more significant <datetime field>. If the
data type of the <datetime value expression> is TIME, then
arithmetic on the HOUR <datetime field> is undertaken modulo
24. If the <interval value expression> or <interval term> is
a year-month interval, then the DAY field of the result is
the same as the DAY field of the <datetime term> or <datetime
value expression>.

c) If, after the preceding step, any <datetime field> of the
result is outside the permissible range of values for the
field or the result is invalid based on the natural rules for
dates and times, then an exception condition is raised: data
exception-datetime field overflow.

关于oracle - 安全的 INTERVAL 算术,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7266703/

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