java - 在 JDeveloper 12c 中测试 Web 服务

Question

我使用 JDeveloper 12c 制作了非常简单的 Web 服务。我有一个名为 Person 的类:

package testapp;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Person {
    private String firstname;
    private String lastname;    
    public Person() {super();}    
    public Person(String firstname, String lastname) this.firstname=firstname;this.lastname=lastname;}
    public void setFirstname(String firstname) {this.firstname = firstname;}
    public String getFirstname() {return firstname;}
    public void setLastname(String lastname) {this.lastname = lastname;}
    public String getLastname() {return lastname;}
}

...和一个 PersonService 类:

package testapp;
import java.util.ArrayList;
import java.util.List;
import java.sql.*;
public class PersonService {
    private List<Person> persons;
    public PersonService() {
        super();
        this.persons = new ArrayList<Person>();
        try {
            Class.forName("oracle.jdbc.driver.OracleDriver");
        } catch (ClassNotFoundException e) {
            System.out.println("ERROR: Cannot find Oracle driver!");
            e.printStackTrace();
            return;
        }
        System.out.println("STATUS: Oracle JDBC Driver Registered!");
        Connection connection = null;
        PreparedStatement preparedStatement = null;
        try {
            connection = DriverManager.getConnection(/* my database connection parameters */);
        } catch (SQLException e) {
            System.out.println("ERROR: Connection Failed! Check output console!");
            e.printStackTrace();
            return;
        }
        if (connection != null) {
            System.out.println("STATUS: Connection established.");
        } else {
            System.out.println("ERROR: Failed to establish connection!");
        }
        try {
            String selectSQL = "/* select first and last name from database */";
            preparedStatement = connection.prepareStatement(selectSQL);
            ResultSet rs = preparedStatement.executeQuery();
            while (rs.next()) {
                this.persons.add(/* Get data from database and make new Person */);
            }
        } catch (SQLException e) {
            System.out.println(e.getMessage());
        } finally {
            try {
                if (preparedStatement != null) {
                    preparedStatement.close();
                }
                if (connection != null) {
                    connection.close();
                }
            } catch (Exception e) {
                System.out.println("ERROR: Something is seriously wrong...");
            }
        }
    }
    public List<Person> getPersons() {return this.persons;}
    public void addPerson(String firstname, String lastname) {
        if (firstname != null && lastname != null) {
            System.out.println("Hello, "+firstname+" "+lastname+"!");
        } else {
            System.out.println("ERROR: First name or last name is null!");
        }
    }
}

我已关注this tutorial制作网络服务并测试它。我选择了 application/xml 和 application/json 类型的参数。最后，我的 addPerson 方法如下所示:

@POST
@Consumes(value = { "application/json", "application/xml" })
@Path("/person")
public void addPerson(@FormParam("firstname") String firstname, @FormParam("lastname") String lastname) {
    if ((firstname != null) && (lastname != null)) {
        System.out.println("Hello, "+firstname+" "+lastname+"!");
    } else {
        System.out.println("ERROR: First name or last name is null!");
    }
}

我能够测试我的 GET 方法 (getPersons)，并且得到一个漂亮的响应。但我不知道如何测试 POST 方法(addPerson)，即我不知道如何提供参数。这是屏幕截图:

我尝试单击绿色加号(添加 header )，然后将 header 名称更改为“名字”和“姓氏”并设置一些值，但是当我单击“发送请求”时，出现错误消息(名字或姓氏为空)。

输入某些输入参数的正确方法是什么？

Answer 1

FormParam 需要一个可以获取参数的表单。如果要对此进行测试，请在服务中将参数类型更改为 PathParam 或 QueryParam。这样，您就可以使用分析仪对其进行测试。因此，对于 QueryParam，您的 addPerson 将如下所示:

public void addPerson(@QueryParam("firstname") 字符串名字, @QueryParam("lastname") 字符串姓氏) {::}

在分析器中，您只需将 ?firstname=ABC&lastname=XYZ 附加到 URL 并发送请求即可。