PHP readdir() : 3 is not a valid Directory resource

Question

    <?php

function convert(){

 //enable error reporting for debugging
 error_reporting(E_ALL | E_STRICT);

 //convert pdf's to html using payroll.sh script and
 //pdftohtml command line tool
 $program = "payroll.sh";
 $toexec="sh /var/www/html/tmp/" . $program . " 2>&1";
 $exec=shell_exec($toexec);

 //display message from payroll.sh
 //echo $exec;
 //echo ('<br/>');

}

function process(){

$dir = '/var/www/html/tmp/converted';
//echo ('one');

if (is_dir($dir)) {
//echo ('two');
    if ($dh = opendir($dir)) {
 //echo ('three');
        while (($file = readdir($dh)) !== false) {
  //echo ('four');

   if ($file != "." && $file != ".."){
   echo 'opening file: ';
   echo $file;
   echo ("<br/>");
   $fp = fopen('/var/www/html/tmp/converted/' . $file, 'r+');
   $count = 0;

      //while file is not at the EOF marker
      while (!feof($fp)) 
       {
        $line = fgets($fp);

        if($count==21)
         {
         $employeeID = substr($line,71,4);
         echo 'employee ID: ';
         echo $employeeID;
         echo ('<br/>');
         //echo ('six');
         $count++;
         }
        else if($count==30)
         {
         $employeeDate = substr($line,71,10);
         echo 'employee Date: ';
         echo $employeeDate;
         echo ('<br/>');
         //echo ('seven');
         $count++;
         }
        else 
         {
         //echo ('eight');
         //echo ('<br/>');
         $count++;
         }
         }
   fclose($fp);
   closedir($dh);

}
}
}
}
}

convert();
process();
?>

我正在设置一个 php 脚本，它将采用 pdf 格式的工资单，将其转换为 html，然后在获取日期和员工 ID 后将其导入 Drupal。

代码似乎只处理目录中的第一个文件然后它给了我这个:

opening file: dd00000112_28_2010142011-1.html
employee ID: 9871
employee Date: 12/31/2010<p></p>

<p>Warning: readdir(): 3 is not a valid Directory resource in /var/www/html/pay.mistequaygroup.com/payroll.php on line 29
</p>

错误中的“3”真的让我很困惑，谷歌也帮不上什么忙。它可能是循环的第 3 次迭代吗？ reddir() 正在扫描的目录中唯一的文件是等待处理的 .html 文件。有什么想法吗？

此外，我的代码看起来如何？我对进行任何真正的编程都是相当陌生的，而且我没有在工作中得到太多的投入。

Answer 1

看起来您在完成目录之前就关闭了目录。移动这一行:

closedir($dh);

在 while 循环之外:

while (($file = readdir($dh)) !== false) {
   ....
}
closedir($dh);

而不是这个:

while (($file = readdir($dh)) !== false) {
   ....
   closedir($dh);
}