azure - 如何从 Azure Devops REST API 仅返回特定属性

Question

我正在尝试使用以下命令获取 Azure Devops 中特定项目的所有构建详细信息获取:https://dev.azure.com/{organization}/{project}/_apis/build/builds?api-version=5.1

此 API 返回具有许多属性的 JSON 对象。在 Jenkins API 中，我们可以仅过滤所需的属性。Azure Devops API 中是否有类似的方法？

根据文档https://learn.microsoft.com/en-us/rest/api/azure/devops/build/builds/get?view=azure-devops-rest-5.1，我尝试使用 propertyFilter 但没有帮助我。

任何帮助或指示都会有用。

Answer 1

从 DevOps 返回的 JSON 看起来非常像这样:

{
  "count": 1000,
  "value": [
    {
      "id": ,
      "buildNumber": "",
      "status": "",
      "result": "",
      "queueTime": "",
      "startTime": "",
      "finishTime": "",
      "url": "",
      "definition": {
        "drafts": [

        ],
        "id": ,
        "name": "",
        "url": "",
        "uri": "",
        "path": "",
        "type": "",
        "queueStatus": "",
        "revision": ,
        "project": {
          "id": "",
          "name": "<NAMEOFYOURPROJECT>",
          "url": "",
          "state": "",
          "revision": ,
          "visibility": "",
          "lastUpdateTime": ""
        }
      },
      "buildNumberRevision": 2,
      "project": {
        "id": "",
        "name": "<NAMEOFYOURPROJECT>",
        "url": "",
        "state": "",
        "revision": ,
        "visibility": "",
        "lastUpdateTime": "2"
      },
      ...

您要查找的过滤键是 project/name .

要过滤的 ODATA 查询字符串 project/name看起来像这样: https://dev.azure.com/{organization}/{project}/_apis/build/builds?api-version=5.1&$filter=startswith(project/name,'<NAMEOFYOURPROJECT>')