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java - JPopupMenu 在鼠标输入时消失

转载 作者:行者123 更新时间:2023-12-02 06:39:42 26 4
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我有下一个结构:JPopupMenu包含JPanel,其中包含JMenuItems。问题是,我无法使用它,因为当鼠标进入任何菜单项时,JPopupMenu就会消失。

SSCCE:

public class PopupTest {
public static void main(String[] a) {
final JFrame frame = new JFrame();
frame.setSize(500, 500);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

final JPanel panel = new JPanel(new BorderLayout());
panel.setBorder(BorderFactory.createLineBorder(Color.RED));

panel.addMouseListener(new MouseAdapter() {
@Override
public void mouseClicked(MouseEvent e) {
if (e.getButton() == MouseEvent.BUTTON3) {
final JPopupMenu menu = new JPopupMenu();
JPanel menuPanel = new JPanel();
menuPanel.setBorder(BorderFactory.createLineBorder(Color.GREEN));
menuPanel.setLayout(new BoxLayout(menuPanel, BoxLayout.Y_AXIS));

for (int i = 0; i < 10; i++) {
JMenuItem item = new JMenuItem(String.valueOf(i));
menuPanel.add(item);
}

menu.add(menuPanel);
menu.show(panel, e.getX(), e.getY());
}
}
});
frame.setContentPane(panel);
frame.setUndecorated(true);
frame.setBackground(new Color(50, 50, 50, 200));

SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
frame.setVisible(true);
}
});
}
}

顺便说一句,当 JPopupMenu 及其项目之间没有 JPanel 时,问题不会重复。

有谁知道如何防止这种情况吗?

最佳答案

没有直接回答您的问题,但我认为,当它支持直接添加 JMenuitem 时,您没有必要向 JPopupMenu 添加带有框布局的 panel到它。检查以下代码片段:

                 final JPopupMenu menu = new JPopupMenu();
JPanel menuPanel = new JPanel();
menuPanel.setBorder(BorderFactory.createLineBorder(Color.GREEN));
// menuPanel.setLayout(new BoxLayout(menuPanel, BoxLayout.Y_AXIS));

for (int i = 0; i < 10; i++) {
JLabel item = new JLabel(i+"");
menuPanel.add(item);
}

menu.add(menuPanel);

menu.show(panel, e.getX(), e.getY());

关于java - JPopupMenu 在鼠标输入时消失,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19274865/

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