gpt4 book ai didi

java - 如何以不同的方法从数组列表中选择大小写

转载 作者:行者123 更新时间:2023-12-02 06:37:34 26 4
gpt4 key购买 nike

我目前正在用java制作一个绞刑吏游戏,我在一种方法中按难度组织了单词列表,然后在另一种方法中,我有一个if语句询问用户想玩哪个难度。我该怎么做呢?我的代码如下:

public static int word(){
String words[] = new String[26];
switch(diff){
case 1:
words[0] = "cat";
words[1] = "dog";
words[2] = "book";
words[3] = "breakfeast";
words[4] = "telephone";
words[5] = "mixture";
words[6] = "music";
words[7] = "animal";
words[8] = "school";
words[9] = "plant";
words[10] = "pen";
words[11] = "pencil";
words[12] = "paper";
words[13] = "note";
words[14] = "fog";
words[15] = "smoke";
words[16] = "bake";
words[17] = "alone";
words[18] = "drive";
words[19] = "town";
words[20] = "city";
words[21] = "sunny";
words[22] = "shine";
words[23] = "polish";
words[24] = "cap";
words[25] = "hat";

break;
case 2:
words[0] = "president";
words[1] = "exclamation";
words[2] = "statement";
words[3] = "television";
words[4] = "physics";
words[5] = "algebra";
words[6] = "geometry";
words[7] = "difficult";
words[8] = "extreme";
words[9] = "procedure";
words[10] = "ship";
words[11] = "soldier";
words[12] = "lunch";
words[13] = "hockey";
words[14] = "tennis";
words[15] = "soccer";
words[16] = "football";
words[17] = "basketball";
words[18] = "bias";
words[19] = "magazine";
words[20] = "computer";
words[21] = "internet";
words[22] = "allegedly";
words[23] = "system";
words[24] = "unison";
words[25] = "excited";
break;
case 3:
words[0] = "amalgamation";
words[1] = "proclomation";
words[2] = "establishment";
words[3] = "rehabilitation";
words[4] = "rhinoceros";
words[5] = "velociraptor";
words[6] = "declaration";
words[7] = "announcement";
words[8] = "binomial";
words[9] = "polynomial";
words[10] = "congregation";
words[11] = "obligation";
words[12] = "structure";
words[13] = "description";
words[14] = "perscription";
words[15] = "subscribe";
words[16] = "address";
words[17] = "township";
words[18] = "mischievous";
words[19] = "bewildered";
words[20] = "accusation";
words[21] = "designation";
words[22] = "disgusting";
words[23] = "prolonged";
words[24] = "restoration";
words[25] = "regeneration";
}

int i = words.length;

Random rng = new Random(); //This block of code chooses random word from array list
int choice = rng.nextInt(words.length); //Varible storing random word
String wd = words[choice];
out.println(wd);
}



public static int gameStart(){
Scanner qwe = new Scanner(in);
out.println("Welcome to my Hang Man game!\n");
out.println("What difficulty would you like to play on?\t1-3");
int diff = qwe.nextInt();

if (diff == 1){
//not sure what would go here
}
else if (diff == 2){
//not sure what would go here
}
else{
//not sure what would go here
}


}

最佳答案

  1. 将每个难度的单词存储在单独的文本文件中。
  2. 创建一个方法String[] getWords(intdifficulty),该方法将返回从文件加载的给定难度的单词列表。
  3. 不要在一个方法中混合处理程序不同方面的代码 - 就像在 word() 方法中那样。创建单词列表、选择随机单词并将其显示在屏幕上听起来像是三个不同的方面。这大约意味着 3 种方法。

关于java - 如何以不同的方法从数组列表中选择大小写,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19481129/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com