java - 将数组字符串替换为其他数组字符串

Question

同一主题:replace String with another in java

我想替换String Replace = "SUM(NewCounter)+SUM(NewCounter2)+NewCounter3";

我有数组 A = {NewCounter, NewCounter2, NewCounter3}
假设我有Array B = {test, testA, testB}

我想用字符串Replace中的数组A和数组B替换它。
我尝试使用方法 ReplaceAll(A.get(index), B.get(index));

问题是:

NewCounter2 被系统读取 "NewCounter"+2
所以我有 result = String Replace = "SUM(test)+SUM(test2)+test3";

我尝试在字符 NewCounter 中使用 '，它将是 Array A = {'NewCounter', 'NewCounter2', 'NewCounter3'}

但我必须像这样更改字符串Replace之前:

String Replace = "SUM('NewCounter')+SUM('NewCounter2')+'NewCounter3'";

我还有其他办法吗？？？我不想之前更改字符串...

谢谢，

-mazipan-

Answer 1

同时替换的最简单解决方案是按长度递减的顺序处理字符串。这将正确地进行替换:

A = {NewCounter3, NewCounter2, NewCounter}
B = {testB, testA, test}

但是，如果任何搜索字符串可以与替换字符串匹配，则此技术将不起作用。

编辑:对于一般情况，我写了这个:

public static String simultaneousReplace(String subject,
        String[] find, String[] replace) {
    if (find.length != replace.length) throw new IllegalArgumentException(
        "Strings to find and replace are not paired.");
    int numPairs = find.length;
    StringBuilder sb = new StringBuilder();
    for (int i = 0, len = subject.length(); i < len; i++) {
        int longestMatchIndex = -1;
        int longestMatchLength = -1;
        for (int j = 0; j < numPairs; j++) {
            String find1 = find[j];
            if (subject.regionMatches(false, i, find1, 0, find1.length())) {
                if (find1.length() > longestMatchLength) {
                    longestMatchIndex = j;
                    longestMatchLength = find1.length();
                }
            }
        }
        if (longestMatchIndex >= 0) {
            sb.append(replace[longestMatchIndex]);
            i += longestMatchLength - 1;
        } else {
            sb.append(subject.charAt(i));
        }
    }
    return sb.toString();
}

使用示例:

String s = "SUM(NewCounter)+SUM(NewCounter2)+NewCounter3";

s = simultaneousReplace(s,
    new String[] { "NewCounter", "NewCounter2", "NewCounter3" },
    new String[] { "test", "testA", "testB" }
);

System.out.println(s);

输出:

SUM(test)+SUM(testA)+testB