Java:从另一个方法传递数组

Question

我有一个项目，有四种方法。第二种和第三种方法(分别有和没有)都有数组供用户输入数据。

下面是第二种方法的示例。第三个很像

public static void billWithoutGardens()
{
    Scanner input = new Scanner(System.in);

    double withoutGardens[] = new double[12];

    System.out.println("Please enter energy bills for year without rooftop gardens");
    // 12 part array, one for each month
    System.out.print("Please enter energy bill for January: ");
    withoutGardens [0] = input.nextDouble();
    System.out.print("Please enter energy bill for February: ");
    withoutGardens [1] = input.nextDouble();
    System.out.print("Please enter energy bill for March: ");
    withoutGardens [2] = input.nextDouble();
    System.out.print("Please enter energy bill for April: ");
    withoutGardens [3] = input.nextDouble();
    System.out.print("Please enter energy bill for May: ");
    withoutGardens [4] = input.nextDouble();
    System.out.print("Please enter energy bill for June: ");
    withoutGardens [5] = input.nextDouble();
    System.out.print("Please enter energy bill for July: ");
    withoutGardens [6] = input.nextDouble();
    System.out.print("Please enter energy bill for August: ");
    withoutGardens [7] = input.nextDouble();
    System.out.print("Please enter energy bill for September: ");
    withoutGardens [8] = input.nextDouble();
    System.out.print("Please enter energy bill for October: ");
    withoutGardens [9] = input.nextDouble();
    System.out.print("Please enter energy bill for November: ");
    withoutGardens [10] = input.nextDouble();
    System.out.print("Please enter energy bill for December: ");
    withoutGardens [11] = input.nextDouble();

    System.out.println(Arrays.toString(withoutGardens));


    return;

我正在尝试使用第四种方法来计算两个数组中每个元素之间的差异。我不知道如何做到这一点，经过大量搜索后，我向 Stackoverflow 的好人求助。

第四种方法是这样的

public static void calculateSavings(double withoutGardens[], double withGardens[])
{

}

为了实现计算差异的目标，这是开始该方法的正确方法吗？

编辑 - 我如何将第四个方法调用回主方法？

calculateSavings(withoutGardens[], withGardens[]);

这就是我现在的情况，但我收到错误，它“无法解析为变量”。

Answer 1

创建一个与 withoutGardens 大小相同的新数组，然后执行循环并将新数组的元素设置为 withoutGardens 和 元素的差值>withGardens.

此外，在您的方法中，您希望返回创建的数组，即 withoutGardens，因为它是 billWithoutGardens() 内部的局部变量，并且在该方法之外不可用。

将方法签名更改为:

public static double[] billWithoutGardens()

最后一行:

return withoutGardens;