java - 程序中的双输出

Question

当我运行代码时，我得到两次输出，而不是一次。这是什么原因造成的？另外，我如何输出计算机猜测单词所需的次数？这是当前的输出:但是当我输入一个单词时，它会输出两次？

Enter a 4 or 5 letter word and the computer will play hangman against you!
nice 
Your word is: nice
Enter a 4 or 5 letter word and the computer will play hangman against you! 

代码

import java.util.Scanner;
import javax.swing.JApplet;
import java.awt.*;

public class Hangman extends JApplet
{
    public void paint (Graphics Page)
    {
                //gallows
                Page.drawLine(0,300,20,300);
                Page.drawLine(10,40,10,300);
                Page.drawLine(10,40,80,40);
                Page.drawLine(80,40,80,55);

                //torso
                Page.drawOval(50,55,50,55);
                Page.drawOval(50,100,50,100);
                //left arm and hand
                Page.drawLine(50,150,40,110);
                Page.drawLine(40,110, 45,100);
                Page.drawLine(40,110, 25,100);
                Page.drawLine(40,110, 25,115);


                //right arm and hand
                Page.drawLine(100,150,120,110);
                Page.drawLine(120,110, 115,95);
                Page.drawLine(120,110, 125,95);
                Page.drawLine(120,110, 135,115);

                //left  leg and foot
                Page.drawLine(80,200,100,250);
                Page.drawLine(100,250, 115,260);


                //right leg and foot
                Page.drawLine(75,200,60,250);
                Page.drawLine(60,250,45,260);




     Scanner in = new Scanner(System.in);
     System.out.println("Enter a 4 or 5 letter word and the computer will play hangman against you!");



     String word = in.nextLine();




     char[] letter = word.toCharArray();


     for (int i = 0; i < letter.length; i++) {
             letter[i] = 'a';
     }


     for (int i = 0; i < word.length(); i++){
         for (int j = 48; j < 122; j++) {

                     if (letter[i] == word.charAt(i)) { 
                             break; 
                     } else {
                             letter[i] = (char)((int) j + 1);
                     }
             }
     }
     System.out.println("Your word is: ");

     for (char letters : letter) {
             System.out.print(letters);
     }

}

}

Answer 1

不要在基于 GUI 的应用程序中使用控制台输入。应通过使用一个或多个可用的 UI 控件来获取用户输入。

Swing 中的绘制可能因多种原因而发生，其中许多原因是您无法控制的，这意味着每当 Swing 想要更新您的 UI 时，它都会调用 Paint，这意味着您会不断被要求提供新的 UI词

此外，您正在阻止绘制过程，这意味着在您绘制方法退出之前，不太可能绘制任何内容

首先查看 How to create a GUI with Swing并且，当您了解这一点时，Performing Custom Painting