java - AsyncTask 返回错误

Question

我一直在尝试使用 Asynctask 解析 XML 文件，遵循 [1]和 [2]教程。我在我的 Activity 中实现了一个类，如下所示:

private class GetRoutes extends AsyncTask<String, Void, String[]> {
        @Override
        protected String[] doInBackground(String... urls) {
          String[] read;
              try{
                RouteReader route = new RouteReader();
                read = route.getRoutes();
            } catch(IOException iox){
                read = new String[1];
                read[0] = getResources().getString(R.string.loading_error);
            } catch(ArrayIndexOutOfBoundsException aiob){
                read = new String[1];
                read[0] = getResources().getString(R.string.loading_error);
            } catch(NullPointerException npe){
                read = new String[1];
                read[0] = getResources().getString(R.string.loading_error);
            }
          return read;
        }

        @Override
        protected void onPostExecute(String[] result) {
          values = result;
        }
      }

然后在我的 onCreate 方法中将其调用为 new GetRoutes().execute("test");。 但是，当我尝试运行此程序时，我的应用程序因 NullPointerException ( logcat is available here ) 而崩溃。

您能指导我如何解决这个问题吗？

<小时/>

为了进一步引用，我的 RouteReader 类如下:

public class RouteReader extends Reader{
public final static String routeURL = 
        "http://webservices.nextbus.com/service/publicXMLFeed?command=routeList&a=ttc";
private Map<String, String> routes;

public RouteReader() 
        throws IOException, ArrayIndexOutOfBoundsException{
    super(new URL(routeURL));
    routes = xmlToMap();
}

public String[] getRoutes(){
    return (String[]) routes.keySet().toArray();
}

public String getRouteNum(String route){
    return routes.get(route);
}

private Map<String, String> xmlToMap() 
        throws IOException, ArrayIndexOutOfBoundsException{
    Map<String, String> data = new HashMap<String, String>();
    String input;
    do{
        input = getReader().readLine();
        if (input.startsWith("<route")){
            String[] read = input.split("\"");
            data.put(read[3], read[1]);
        }
    }while (!input.equals("</body>"));
    return data;
}

}

Answer 1

来自您的日志:

Caused by: java.lang.NumberFormatException: Invalid int: "1S"

这可能是由这一行引起的:

data.put(read[3], Integer.parseInt(read[1]));