java - 当 NumberFormatException 时如何使用有问题的输入字符串打印自定义消息

Question

线程“main”中出现异常java.lang.NumberFormatException:对于输入字符串:“a”

如何访问导致 NumberFormatException 以这种形式打印自定义错误消息的输入字符串:

try {
    /* some code which includes many Integer.parseInt(some_string); */
}
catch (NumberFormatException nfe) {
    System.out.println("This is not a number: " + input_string_which_causing_the_error);
}

那么我应该得到:

This is not a number: a

Answer 1

您可以从异常中提取它:

} catch (NumberFormatException e) {
    System.err.println(e.getMessage().replaceFirst(".*For input string: ", "This is not a number"));
}