php - mysql_close() 期望参数 1 为资源，给定为空

Question

导致错误的行是这一行...

mysql_close($con);

这是完整的代码...

$con=mysqli_connect("localhost","root","pass","db_name");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM medicos");


    while($row = mysqli_fetch_array($result)) {
    echo '.....';
    }



    mysql_close($con);

Answer 1

行 mysql_close($con); 必须更改为 mysqli_close($con);

您不能互换使用 mysql 和 mysqli 函数，例如:

mysqli_connect 需要使用 mysqli_close

-同样-

mysql_connect 需要使用 mysql_close