java - 如何从 Activity 外部移动到另一个 Activity android

Question

我想知道是否有办法通过在您想要离开的 Activity 之外发出命令来移动当前 Activity 。

我向你展示我得到了什么:

这是我的启动屏幕 Activity :

public class SplashScreen extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_splash_screen);
    SQLHelper sqlHelper = new SQLHelper(this);
    InfosModel infos = sqlHelper.getInfos();
    RequestModel request = new RequestModel();
    if (infos.getToken().length() == 0){
        request.setType("password");
        new OAuthHelper().execute(request);
    }
 }
}

这是我的 OAuthHelper:

public class OAuthHelper extends AsyncTask<RequestModel, Void, TokenModel> {

public OAuthHelper(){
}

@Override
protected void onPreExecute(){
}

@Override
protected void onPostExecute(TokenModel models){
    if (models == null){
        Log.i("infos", "You have no internet connection or the server is unreachable !");
    }
    else{
        Log.i("infos", "request's done with success !");
    }

}

@Override
protected TokenModel doInBackground(RequestModel... request) {
    try
    {
        try
        {
             HttpClient httpclient = new DefaultHttpClient();
             HttpPost httppost = new HttpPost("http://api.listopresto.com/oauth/token");
             List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
             if (request[0].getType() == "password"){
               /* Some Params */
             }
             else{
                 return (null);
             }
             httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs, HTTP.UTF_8));
            HttpResponse response = httpclient.execute(httppost);
            BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
            String s = reader.readLine();
            Log.i("infos", s);
            Gson gson = new Gson();
            TokenModel tokenObj;
            tokenObj = gson.fromJson(s, new TypeToken<TokenModel>(){}.getType());
            return (tokenObj);
        } catch (ClientProtocolException e) {
            Log.i("infos", "first");
            return (null);
        } catch (IOException e) {
            Log.i("infos", "second");
            return (null);
        }
    }
    catch (Exception e){
        Log.i("infos", "third");
        return (null);
    }
}   
}

如果我将我的助手粘贴到spashscreen类中，我当然可以移动到另一个 Activity ，但这是一个助手，我的意思是我必须从其他地方再次使用它，我当然不这样做不想再经过我的启动画面...

我想要的是从我的启动屏幕转移到好的启动屏幕，具体取决于我从服务器获得的答案...我想在 postExecute 方法中给出该命令..

有办法做到这一点吗？

谢谢你!! ;)

Answer 1

将上下文传递给Asynctask的构造函数

new OAuthHelper(SplashScreen.this).execute(request);

然后

Context context;
public OAuthHelper(Context context){
    this.context= context;
}

在doInbackground中进行后台工作。在 doInbackground 中返回结果。

然后在基于响应的onPostExecute中

context.startActivity(new Intent(context,SecondActivity.class));

另一种选择是使用接口(interface)作为对 Activity 的回调，然后从 Activity 本身启动 Activity 。在下面的链接中查看 blackbelt 的答案

How do I return a boolean from AsyncTask?