Java比较对象列表以查找重复项并将它们放入新列表中

Question

当比较同一对象的两个列表以查找它们的重复位置时，两个列表都为空。

List<Appointment> appointmentByName = sM.getAppointmentByName(first.getText(),last.getText());
List<Appointment>appointmentByDate=sM.getAppointmentByDate(LocalDate.now());System.out.println(appointmentByName);
//Populating the lists (This works)


List<Appointment> common = appointmentByDate.stream().filter(appointmentByName::contains).collect(toList());

填充列表后，我想找到相同的约会对象并将它们放入新列表中，例如

List1 [Appointment@20, Appointment@c3, Appointment@d9, Appointment@175]
List2 [Appointment@23, Appointment@175]
List3 [Appointment@175]

等于 Appointment 类中的覆盖

public boolean equals(Object o) {
    if (this == o) return true;
    if (!(o instanceof Appointment)) return false;
    Appointment that = (Appointment) o;
    return id == that.id;
}

但是通用列表是空的，我们将不胜感激。

Answer 1

不确定我是否正确理解你的问题，但在我看来，你试图在这里做两个列表的交集。如果是，您可以使用 Collection 的 keepAll() 方法来完成:

list1.retainAll(list2)

list1 现在将仅包含两个列表的重复项