java - 我的剪刀石头布游戏不会显示平局

Question

我已经用 BlueJ 编写了这段石头剪刀布代码，到目前为止一切都运行良好......除了一件事。当我与电脑连接时，游戏不会告诉我。它会告诉我计算机使用了什么，它会告诉我是赢了还是输了。然而，如果我打了平局，它只会告诉我计算机使用了什么，并忽略平局。代码如下。~~~

/**
*A simple game of Rock Paper Scissors.
*
*@author Erik Ingvoldsen
*@version 1.0
*/

import java.util.Scanner;
import java.util.Random;
public class Rock
{
public static void main(String[] args)
{
String playAgain = "4";    
do
    {
    String personPlay;
    String computerPlay = "";
    int computerInt;
    String response;
    Scanner scan = new Scanner(System.in);
    Random generator = new Random();
    System.out.println("   ");
    System.out.println("Press 1 for Rock, 2 for Scissors, 3 for Paper, and 4 to quit.");
    System.out.println();
    computerInt = generator.nextInt(3)+1;
    if (computerInt == 1)
       computerPlay = "Rock";
    else if (computerInt == 2)
       computerPlay = "Scissors";
    else if (computerInt == 3)
       computerPlay = "Paper";
    //1=Rock 2=Scissors 3=Paper
    {System.out.println("Rock Paper Scissors: ");
    {personPlay = scan.next();
    System.out.println("Computer chooses: " + computerPlay);
    if (personPlay.equals(computerPlay)){ 
       System.out.println("It's a tie!");}
    else if (personPlay.equals("1")){
       if (computerPlay.equals("Paper"))
          System.out.println("Paper beats rock. Loser.");
    else if (computerPlay.equals("Scissors"))
            System.out.println("Rock beats scissors. Winner.");}
    else if(personPlay.equals("2")){
       if (computerPlay.equals("Paper"))
          System.out.println("Scissors beats paper. Winner");
    else if (computerPlay.equals("Rock"))
            System.out.println("Rock beats scissors. Loser.");}
   else if (personPlay.equals("3")) {
       if (computerPlay.equals("Rock"))
          System.out.println("Paper beats rock. Winner.");
   else if (computerPlay.equals("Scissors"))
            System.out.println("Scissors beats paper. Loser.");}
   else
System.out.println("Not a valid key. Cheaters never win.");}
System.out.println("Press 4 to quit or any other key to continue.");
Scanner End = new Scanner(System.in);
String quit=End.nextLine();
if(quit.equals("4"))
{
System.exit(0);}
}
}while(true);
}
}

Answer 1

您似乎正在尝试比较 "1"至"Paper"并期待true .

要么进行两个比较true ，即将用户输入与 "1" 进行比较并将计算机发送至"Paper" ，或翻译"1"至"Paper" (以及相应的其他两个值)并直接比较响应。