java - 在java程序中的方法中计算最大投篮命中率

Question

必须在一组球队投篮命中率数据中找到最大值和最小值。

import java.io.*;
import java.util.Scanner;
public class kstatebball
{
    public static void main(String [] args)
    throws FileNotFoundException
    {
        Scanner in = new Scanner(new File("data1.txt"));
        String[] firstname = new String [100];
        String[] lastname = new String [100];
        int fgm[] = new int [100];
        int fga[] = new int [100];
        double fgp = 0;        
        int maxFGP;
        int minFGP;              

        System.out.print("         Player              FGM     FGA             FGP%\n");
        int  count = 0;
        for( int i = 0;in.hasNext(); i++)
        {
            firstname[i] = in.next(); 
            lastname[i] = in.next();
            fgm[i] = in.nextInt();
            fga[i] = in.nextInt();
            fgp = (1.0 * fgm[i]) / (1.0 * fga[i]) * 100;
            count++;           
            System.out.printf("%10s %10s        %3d     %3d             %3.1f  \n",firstname[i],lastname[i],fgm[i],fga[i],fgp);            
        }
        maxFGP = maxFGP(fgm,fga,count);
        minFGP = minFGP(fgm,fga,count);
        System.out.printf("\n\nThe player with the highest field goal percentage is: %3d ",maxFGP(fgm,fga,count));
        System.out.printf("\nThe player with the lowest field goal percentage is : %3.1f",fgp);
    }

    public static int maxFGP(int[] fgm, int[] fga, int count)
    {
        int max = 0;
        for(int i = 0; i < count; i++)
        {
            if((1.0 * fgm[i]) / (1.0 * fga[i]) * 100 > max) 
                max = i;            
        }
        return max;
    }



    public static int minFGP(int[]fgm, int[]fga, int count)
    {
        int min = 0;
        for(int i = 0; i > 13; i++)
        {
            if(fgm[i] > fgm[count])
                count = i;            
        }
        return min;
    }        
}

需要“if”语句的帮助才能返回正确的最大值。

我们有所有球员的百分比，但需要使用这些方法来找到投篮命中率最高和最低的球员。

这是我正在使用的数据文件:

Marcus Foster    123   288
Thomas Gipson    102   178
Shane Southwell  88    224
Will Spradling   58    144
Wesley Iwundu    53    111
Nino Williams    49    96
Nigel Johnson    28    80
Jevon Thomas     15    58
D.J. Johnson     34    68
Omari Lawrence   27    65
Shawn Meyer      2     4
Ryan Schultz     2     9
Jack Karapetyan  1     4
Brian Rohleder   1     2

Answer 1

应该是这样的:

public static int maxFGP(int[] fgm, int[] fga, int count)
{
    int max = 0;
    double maxValue=(1.0 * fgm[0]) / (1.0 * fga[0]) * 100;
    for(int i = 0; i < count; i++)
    {
        if((1.0 * fgm[i]) / (1.0 * fga[i]) * 100 > maxValue)                                                      
        {
            max = i;  
            maxValue=(1.0 * fgm[i]) / (1.0 * fga[i]) * 100;  
        }        
    }
    return max;
}

注意:您已经设置了 int max = 0;，因此无需从 i=0 循环。改为 int i=1

要打印具有最大值的玩家的名称:

System.out.printf("\n\nThe player with the highest field goal percentage is: %3d ",firstname[maxFGP(fgm,fga,count)]);