java - (作业)运行，但没有返回我需要的值

Question

我对编程很陌生。我知道循环会让这看起来更有效率。但现在，我只需要弄清楚如何返回正确的值。我需要根据它们的值(value)找出最好的动物。应返回最高值。

• 我已将语句中的比较代码更改为 .equals，所以现在 Surveyresponse.equals("answer") 它并没有解决我的问题。

• 代码当前正在运行，但仅返回 dragon 作为答案。

• 我需要代码来返回具有最高值(value)的动物。

• 任务要求狗赢得所有平局，而猫总是输掉平局。

  import java.util.Scanner;
  
  public class PetSurvey{
   public static void main(String[] args){
    String surveyResponse;
   String y;
    int dogScore, catScore, dragonScore, z;
   dogScore = 0;
   catScore = 0;
   dragonScore = 0;
   z = 0;
   y = "best animal";
  
   Scanner foo = new Scanner( System.in );
  System.out.print(" What is your favorite pet? ");
  System.out.print(" a) Dogs ");
  System.out.print(" b) Cats ");
  System.out.print(" c) Dragons ");
  System.out.print(" d) I like cats, dogs and dragons ");
  surveyResponse = foo.next();
  if (surveyResponse == "a"){
      dogScore = dogScore + 3;}
  if (surveyResponse == "b"){
      catScore = catScore + 3;}
  if (surveyResponse == "c"){
      dragonScore = dragonScore + 3;}
  if (surveyResponse == "d"){
      dogScore = dogScore + 1; 
      catScore = catScore + 1; 
      dragonScore = dragonScore +1;}
  
  System.out.print(" What is your favorite pet? ");
  System.out.print(" a) Dogs ");
  System.out.print(" b) Cats ");
  System.out.print(" c) Dragons ");
  System.out.print(" d) I like cats, dogs and dragons ");
  surveyResponse = foo.next();
  if (surveyResponse == "a"){
      dogScore = dogScore + 3;}
  if (surveyResponse == "b"){
      catScore = catScore + 3;}
  if (surveyResponse == "c"){
      dragonScore = dragonScore + 3;}
  if (surveyResponse == "d"){
      dogScore = dogScore + 1; 
      catScore = catScore + 1; 
      dragonScore = dragonScore +1;}
  
  System.out.print(" What is your favorite pet? ");
  System.out.print(" a) Dogs ");
  System.out.print(" b) Cats ");
  System.out.print(" c) Dragons ");
  System.out.print(" d) I like cats, dogs and dragons ");
  surveyResponse = foo.next();
  if (surveyResponse == "a"){
      dogScore = dogScore + 3;}
  if (surveyResponse == "b"){
      catScore = catScore + 3;}
  if (surveyResponse == "c"){
      dragonScore = dragonScore + 3;}
  if (surveyResponse == "d"){
      dogScore = dogScore + 1; 
      catScore = catScore + 1; 
      dragonScore = dragonScore +1;}
  
  if (dogScore > z){
  z = dogScore;}
  if (catScore > z){
  z = catScore;}
  if (dragonScore > z){
  z = dragonScore;}
  if (dogScore == catScore){
  z = dogScore;}
  if (catScore == dragonScore){
  z = dragonScore;}
  
  if (z == dogScore){
  y = "dog";}
  if (z == catScore){
  y = "cat";}
  if (z == dragonScore){
  y = "dragon";}
  
  System.out.print(" The most popular pet is: " + y + ".");
  }
  
  }
  

如果有任何帮助，我将不胜感激，提前致谢。

Answer 1

看来您的问题可能与您在代码末尾比较分数的方式有关。

您可以通过首先将狗的分数与其他分数进行比较(因为狗赢得所有平局)，然后将龙的分数与猫的分数进行比较(因为猫失去所有平局)，从而大大简化事情，如下所示:

if (dogScore >= catScore && dogScore >= dragonScore) {
    y = "dog";
}
else if (dragonScore >= catScore) {
    y = "dragon";
}
else {
    y = "cat";
}

这样您就可以完全摆脱 z 并只专注于比较每只动物的实际分数。

我希望这会有所帮助，但如果不清楚，请告诉我。